Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Answer:
This is simple,
Step-by-step explanation:
If the bus costs 200$ and the fair charges 4$ per students that means you have to do this:
300$ budget - 200 of the bus = 100$ left
and if $4 per student:
100 divided by 4 = 25
she can take 25 students
Hope this helps!
1) 1/4+1/2
We need to convert the fractions.
1/4 is fine.
1 x 2=2
2 x 2=4
1/4+2/4=3/4
2) a+a
a can be written as 1a.
1a+1a=2a
I can't see photos and he doesn't know 3 or 4 and i'm confused on 5.
a=?
Hope it helps?
If two figures or lengths are similar, then the ratios of the corresponding lengths are equal.
Thus, 8/32 =5/x
8x = 160
x = 20 feet
Therefore, the length of the flag pole was 20 feet long
So we can start with the full of possibilities and eliminate them one by one.
The full set is {0,1,2,3,4,5,6,7,8,9}.
Now we know that any prime greater than 2 is odd as otherwise it would have 2 as a factor, so we can eliminate all of these digits that would be an even number, leaving:
{1,3,5,7,9}
We also know that any prime greater than 5 cannot be a multiple of 5 and that all numbers with 5 in the digits are a multiple of 5, so we can eliminate 5.
{1,3,7,9}
We know that 11,13,17 and 19 are all primes, so we cannot eliminate any more of these, leaving the set:
{1,3,7,9} as our answer.
