Answer:
Slope =-1/3
Step-by-step explanation:
(3,2)..... x1 =3, y1=2
(-3,4).... x2=-3, y2 =4
Slope=(y2-y1) /(x2-x1)
Slope=(4-2) /(-3-3)
Slope =2/(-6)
Slope=-1/3
Answer:
r > 2
Step-by-step explanation:
9-3 = 6
6/3 = 2
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Answer:

Step-by-step explanation:
The standard equation of a horizontal hyperbola with center (h,k) is

The given hyperbola has vertices at (–10, 6) and (4, 6).
The length of its major axis is
.



The center is the midpoint of the vertices (–10, 6) and (4, 6).
The center is 
We need to use the relation
to find
.
The c-value is the distance from the center (-3,6) to one of the foci (6,6)





We substitute these values into the standard equation of the hyperbola to obtain:


Answer: The polynomial 3x2 is of one variable with a degree of 2.
The polynomial x2y + 3xy2 + 1 is of two variables a with a degree of 3.
Step-by-step explanation: For this case we have the following polynomials:
3x2
x2y + 3xy2 + 1
We have then:
For 3x2:
Classification: polynomial of one variable:
Degree: 2
For x2y + 3xy2 + 1:
Classification: polynomial of two variables
Degree: 2 + 1 = 3