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Anna007 [38]
3 years ago
9

What is the slope of a line that is perpendicular to Y=1/2x-5

Mathematics
1 answer:
Kruka [31]3 years ago
4 0
I believe the answer to this is -1/2
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4 years ago
The difference of 9 and the quotient of a number t and 6 is 5
Strike441 [17]
Assuming you are supposed to solve for the variable "t",

9 - (t ÷ 6) = 5

Subtract 9 from both sides.

9 - 9 - (t ÷ 6) = 5 - 9

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3 0
4 years ago
Place (dlick and drag) one option from each of the lists below Into Its corresponding box to
earnstyle [38]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{3}}x+5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-1}{3}} ~\hfill \stackrel{reciprocal}{\cfrac{3}{-1}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{3}{-1}\implies 3}}

so we're really looking for the equation of a line whose slope is 3 and passes through (1 , 10)

(\stackrel{x_1}{1}~,~\stackrel{y_1}{10})\qquad \qquad \stackrel{slope}{m}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{3}(x-\stackrel{x_1}{1}) \\\\\\ y-10=3x-3\implies y=3x+7

5 0
2 years ago
A tutor earns d dollars per hour. He will be increaseing his hourly wage by 10 percent next month. He tells one of his clients t
Stels [109]
Yes it is correct, because 10 percent is 110/100, which equals to 1.1.

Hope this helps.
8 0
3 years ago
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