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frozen [14]
3 years ago
13

Which state of matter is this?-liquid-amorphous liquid-gas-crystalline solid​

Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
8 0
Gaseous

The atoms are taking up the volume of the entire container
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The O2 produced from the decomposition of the 1.0 L sample of H2O2 is collected in a previously evacuated 10.0 L flask at 300. K
Sergio [31]

The full question can be seen below:

2H_{2}O_2_{(aq)} --> 2H_{2}O_{(l)}+O_{2}_{g}

The decomposition of H_{2}O_{aq} is represented by the equation above.

A student monitored the decomposition of a 1.0 L sample of H_{2}O_2_(_{aq}_) at a constant temperature of 300K and recorded the concentration of H_{2}O_2 as function of time. The results are given in the table below:

                                    Time (s)      H_{2}O_2

                                    0                 2.7

                                    200            2.1

                                    400            1.7

                                    600            1.4

The O_2_(_{g}_) produced from the decomposition of the 1.0 L sample of H_{2}O_2_(_{aq}_) is collected in a previously evacuated 10.0 L flask at 300 K. What is the approximate pressure in the flask after 400 s?

(For estimation purpose, assume that 1.0 mole of gas in 1.0 L exerts a pressure of 24 atm at 300 K).

Answer:

1.2 atm

Explanation:

Considering all assumptions as stated above;

                       2H_{2}O_2_{(aq)} --> 2H_{2}O_{(l)}+O_{2}_{g}

Initial               2.7 mole               ---             ---

Change          -1.0                        ---             +\frac{1.0}{2}

Equilibrium     1.7 mole                ---             0.5 mole

To determine the concentration of O₂; we need to convert the moles to concentration for O₂ = \frac{0.5}{volume in the flask}

                                  = \frac{0.5 mol}{10.0 L}

                                  = 0.05 \frac{mol}{L}

Thus, based on the assumption that "1.0 mole of gas in 1.0 L exerts a pressure of 24 atm"

∴ 0.05\frac{mol}{L} will give rise to = 0.05 \frac{mol}{L} × 24

                                           = 1.2 atm

7 0
3 years ago
Swer questions 12 B D 12 Classify each model A-D as either an ele- ment, a compound, or a mixture. Explain your reasoning for ea
MrRissso [65]

Answer:

13-b

Explanation:

because 13-b is close to a and 12

3 0
3 years ago
Four samples of gas each exert 675 mm Hg in separate 3.5 L containers. What pressure will they exert if they are all placed in a
DedPeter [7]
The pressure that  will  be   exerted if  four sample  of gas are placed in a single  3.5 container  is calculated as below

if  each gas occupies 675  mmhg

what about  4 gases in the sample
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= 675 mm hg x 4/1 = 2.7  x10^3mmhg (answer D)
3 0
3 years ago
One crystalline form of silica (SiO2) has a cubic unit cell, and from X-ray diffraction data it is known that the cell edge leng
tigry1 [53]

Answer:

There are 8Si atoms and 16 O atoms per unit cell

Explanation:

From the question we are told that:

Edge length l=0.700nm=>0.7*10^9nm

Density \rho=2.32g/cm^3

Generally the equation for Volume is mathematically given by

V=l^3

V=(0.7*10^9)m^3

V=3,43*10^-{22}cm

Where

Molar mass of  (SiO2) for one formula unit

M=28+32

M=60g/mol

Therefore

Density of Si per unit length is

\rho_{si}=\frac{9.96*10^{23}}{3.43*10^22}

\rho=0.29

Molar mass of  (SiO2) for one formula unit

M=28+32

M=60g/mol

Therefore

There are 8Si atoms and 16 O atoms per unit cell

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4 years ago
Solid iron(III) hydroxide decomposes to produce iron(III) oxide and water vapor. If 0.75 L of water vapor is produced at STP, ho
MaRussiya [10]
The reaction is 2Fe(OH)3 --> Fe2O3 + 3H2O, so the mole ratio of iron (III) hydroxide to water is 2 to 3, or 0.667. That means you need 0.667 moles of iron(III) hydroxide for every mole of water that forms. 

<span>You are missing some info. You need the volume of the water vapor. At STP, 1 Liter of gas contains 22.4 moles, so you can find the moles of water vapor once you know the volume of the water vapor in Liters. </span>

<span>Then, mulitply moles of water by 0.667 to find moles of iron (III) hydroxide used. Finally, multiply by the molar mass of iron (III) hydroxide to find the mass in grams.</span>
8 0
4 years ago
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