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wolverine [178]
3 years ago
11

What are the values of a, b, and c in the quadratic equation 0 = {x2 – 3x – 2?

Mathematics
1 answer:
vesna_86 [32]3 years ago
6 0

Answer:

a = 1 \\ b =  - 3 \\ c =  - 2

<h3> :-)</h3>
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There was a seller of horses, who sold all his horses to three people. To the first man he sold half of all his horses and a hal
Nata [24]

Answer:

7

Step-by-step explanation:

3RD MAN: 1

2ND MAN: 2

1ST MAN: 4

3rd Man = 1/2+1/2 = 1

2nd Man = 1+1 = 2

1st Man = 2*2 = 4

7 0
3 years ago
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Consider the following data:
-BARSIC- [3]

Answer: x =6

Step-by-step explanation:

8 0
3 years ago
Solve for × and then find the missing angle in<br> the triangle below. SHOW ALL WORK.
Sholpan [36]

Answer:

x = 4°

Step-by-step explanation:

all angles in a triangle sum up to 180°

6x + 38° + 5x + 8° + 90° = 180 °

11x +136° = 180°

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8 0
3 years ago
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HEY GUYS I NEED THIS ANSWER NOW
Sergio [31]

Let

x-------> the number of fiction books

y-------> the number of nonfiction books.

we know that

x+y=26 -----> equation 1

x=y+12

x-y=12 -----> equation 2

Add equation 1 and equation 2

x+y=26\\x-y=12\\ ------\\ 2x=38\\ x=38/2\\x=19\ fiction\ books

<u>find the value of y</u>

x+y=26

19+y=26

y=26-19=7\ nonfiction\ books

therefore

<u>the answer is</u>

Part a)  the number of fiction books is 19\ fiction\ books

Part b)  the number of nonfiction books is 7\ nonfiction\ books

6 0
3 years ago
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The ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years. Approxima
worty [1.4K]

We have been given that the ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years.

We are asked to find the percentage of students that are between 14 and 18 years old.

First of all, we will find z-score corresponding to 14 and 18 using z-score formula.

z=\frac{x-\mu}{\sigma}

z=\frac{14-15}{2}

z=\frac{-1}{2}

z=-0.5

Similarly, we will find the z-score corresponding to 18.

z=\frac{18-15}{2}

z=\frac{3}{2}

z=1.5

Now we will find the probability of getting a z-score between -0.5 and 1.5 that is P(-0.5.

P(-0.5

Using normal distribution table, we will get:

P(-0.5

P(-0.5

Let us convert 0.62465 into percentage.

0.62465\times 100\%=62.465\%\approx 62.5\%

Therefore, approximately 62.5\% of the students are between 14 and 18 years old.

8 0
3 years ago
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