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Alexus [3.1K]
3 years ago
12

3 - 2 tenths. what's the answer?

Mathematics
1 answer:
jeka943 years ago
5 0
Find out yourself.best of luck
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Each bus was filled with 54 students
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2 years ago
Find the value of x, o is the centroid
Ray Of Light [21]

Answer:

x = 14

Step-by-step explanation:

In the triangle O is the centroid.  

Now, we know that the centroid divides the medians in the 2 : 1 ratio that means the distance from the centroid to the vertex and the distance from the centroid to the opposite side remains in 2 : 1 ratio.

So, from the given diagram we can write  

\frac{3x}{2x - 7} = \frac{2}{1}

⇒ 3x = 4x - 14

⇒ x = 14 (Answer)

3 0
3 years ago
Simplified expression of 7z + 8 + 5z – 5z – 9?
Likurg_2 [28]

Answer:

7z-1 hope this helps

Step-by-step explanation:

6 0
2 years ago
Solve for x = 4х – 8 = 3х – 8
Murrr4er [49]

Answer:

x = 4x - 8 - 3x  + 8 = 0 \\ x = 4x - 3x - 8 + 8 = 0 \\ x = 0

4 0
2 years ago
4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail
Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

h^{-1}(x)=\sqrt{\frac{x+1}{3}} ⇒ answer D

Step-by-step explanation:

* <em>Lets explain how to find the inverse of a function</em>

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = f^{-1}(x)

* <em>Lets use these steps to solve the problems</em>

∵ f(x)=\sqrt{x-3}

∵ f(x) = y

∴ y=\sqrt{x-3}

- Exchange x and y

∴ x=\sqrt{y-3}

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by f^{-1}(x)

∴ f^{-1}(x)=x^{2}+3

∵ g(x) = x² + 3

∴ f^{-1}(x)=g(x)

∴ <u><em>The functions are inverses to each other</em></u>

* <em>Now lets find f(g(x))</em>

- To find f(g(x)) substitute x in f(x) by g(x)

∵ f(x)=\sqrt{x-3}

∵ g(x) = x² + 3

∴ f(g(x))=\sqrt{(x^{2}+3)-3}=\sqrt{x^{2}+3-3}=\sqrt{x^{2}}=x

∴ <u><em>f(g(x)) = x</em></u>

∴ The functions are inverses; f(g(x)) = x

* <em>Lets find the inverse of h(x)</em>

∵ h(x) = 3x² - 1 where x ≥ 0

- Let h(x) = y

∴ y = 3x² - 1

- Exchange x and y

∴ x = 3y² - 1

- Add 1 to both sides

∴ x + 1 = 3y²

- Divide both sides by 3

∴ \frac{x + 1}{3}=y^{2}

- Take √ for both sides

∴ ± \sqrt{\frac{x+1}{3}}=y

∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ \sqrt{\frac{x+1}{3}}=y

- replace y by h^{-1}(x)

∴ h^{-1}(x)=\sqrt{\frac{x+1}{3}}

4 0
3 years ago
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