The answer would be a. 288. hope that helped
If a^ x = b then:
x = log_{a}b
For:
4^{7} = 16384 \\ log _{4}16384 = 7
Answer:
Let x be the number of silver medals.
As there were two more gold medals than silver ones, gold medals are x+2
We also know that the number of bronze medals was 4 less than the sum of gold and silver, so if there are x + 2 of gold and x of silver, there are x+x+2-4 of bronze.
Now, we can do an equation, as we know there were a total of 28 medals:
x + x + 2 + x + x + 2 - 4 = 28
And we isolate x:
4x = 28
x = 28/4 = 7
There were 7 silver medals, so there were 9 gold ones (7-2) and 12 of bronze (9+7-4).
Answer:
t = 11.45 years
Step-by-step explanation:
A = p(1+r/n)^nt
A = future value = $12000
P = present value = $6000
n = number of periods = 4
r = interest rate = 6.1% = 0.061
t = number of years = ?
t = log(A/P) / n[log(1 + r/n)]
= log(12000/6000) / 4[log(1+0.061/4)]
= log(2) / 4[log(1 + 0.01525)]
= 0.3010 / 4[log(1.01525)]
= 0.3010 / 4(0.00657)
= 0.3010 / 0.02628
= 11.45 years
