Answer:
Hello your question is incomplete attached below is the correct question
and the solution
answer: A
Step-by-step explanation:
attached below is a detailed solution of the given problem
There exists P and C such that ( ∵ λ1 ≠ λ21 so A is diagonalizable )
-4 _> 4(6y-12)-2y
first distribute/ simplify the equation
-4 _> 24y-48-2y
then combine like terms
-4 _> 22y-48
solve for y
-4 _> 22y-48
44 _> 22y
2 _> y
so the answer is y <_ 2 ( y is less than or equal to 2)
It is the graph of p is steeper than the graph of q.
Answer:
The degrees of freedom for the chi square statistic is 7-4=3
Answer:
Answer: A.) The mean is greater than the median, and the majority of the data points are to the left of the mean.
It is clear that most of the data (around 75%) is consist of value 1, which is the leftmost part of the data. Since it was more than 50% of the data, the median should be 1.
if 75% data is 1, it need 25% data with value at least 5 to make the means equal to 2. The means would be bigger than 1 but less than 2, so most(75% data is 1) of the data would be on the left of the mean.
