Given:
The two functions are:


To find:
The value of
.
Solution:
We have,


We know that,


![(h\circ g)(b)=[(5b-9)-1]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B%285b-9%29-1%5D%5E2)
![(h\circ g)(b)=[5b-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B5b-10%5D%5E2)
Putting
, we get
![(h\circ g)(-6)=[5(-6)-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B5%28-6%29-10%5D%5E2)
![(h\circ g)(-6)=[-39-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-39-10%5D%5E2)
![(h\circ g)(-6)=[-49]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-49%5D%5E2)

Therefore, the value of
is 2401.
Answer:
D
Step-by-step explanation:
Answer:
[(8-3)×5]-1=24
Step-by-step explanation:
[(8-3)×5]-1=24
[(5)×5]-1=24
[5×5]-1=24
[25]-1=24
25-1=24
24=24
The equation represents the line that passes through (–6, 7) and (–3, 6)
.
<h3>What is the slope of the equation?</h3>
For all lines in slope y-intercept form, it would be very simple to just find the answer by finding yourself the slope and y-intercept of the line in question.
The slope of the line is;

The equation represents the line that passes through (–6, 7) and (–3, 6) is;

The required line of the equation is;

Hence, the equation represents the line that passes through (–6, 7) and (–3, 6)
.
To know more about the equation of line click the link given below.
brainly.com/question/8955867
Answer: 0.0228 .
Step-by-step explanation:
Given, IQ scores are approximately normally distributed with a mean of 100 and standard deviation of 15
Let X denotes the IQ score.
Then, the proportion of people with IQs above 130 is
![P(X>130)=P(\dfrac{X-mean}{ standard\ deviation}>\dfrac{130-100}{15})\\\\= P(Z>2)\ \ \ \[Z=\dfrac{X-mean}{ standard\ deviation}]](https://tex.z-dn.net/?f=P%28X%3E130%29%3DP%28%5Cdfrac%7BX-mean%7D%7B%20standard%5C%20deviation%7D%3E%5Cdfrac%7B130-100%7D%7B15%7D%29%5C%5C%5C%5C%3D%20P%28Z%3E2%29%5C%20%5C%20%5C%20%5C%5BZ%3D%5Cdfrac%7BX-mean%7D%7B%20standard%5C%20deviation%7D%5D)

Hence, the proportion of people with IQs above 130 is 0.0228 .