Answer:
x = -1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
0 = 4x + 4
<u>Step 2: Solve for </u><em><u>x</u></em>
- Subtract 4 on both sides: -4 = 4x
- Divide 4 on both sides: -1 = x
- Rewrite: x = -1
Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
Answer:
5x + 4y + 12 = 0
Step-by-step explanation:
Start with the point-slope equation of a straight line: y - k = m(x - h):
Here we are given the point (h, k): (-8, 7) and the slope m = -5/4. Inserting this info into the equation give above, we get: y - 7 = (-5/4)(x + 8).
We must put this equation into "standard form" Ax + By + C = 0.
Multiply all three terms by 4 to remove fractions: 4y - 28 = -5(x + 8), or
4y - 28 + 5x + 40 = 0
Rearranging these terms, we get 5x + 4y + 12 = 0, which is the desired equation in standard form.
Answer:
Step-by-step explanation:
Given are 3 data sets with values as:
(i) 8 9 10 11 12 ... Mean =10
(ii) 7 9 10 11 13 ... Mean =10
(iii) 7 8 10 12 13 ... Mean =10
We see that data set shows mean deviations as
(i) -2 -1 0 1 2
(ii) -3 -1 0 1 3
(iii) -3 -2 0 2 3
Since variance is the square of std deviation, we find that std deviation is larger when variance is larger.
Variance is the sum of squares of (x-mean). Whenever x-mean increases variance increases and also std deviation.
Hence we find that without calculations also (i) has least std dev followed by (ii) and then (iii)
(i) (ii) (iii) is the order.
b) Between (i) and (ii) we find that 3 entries are the same and 2 entries differ thus increasing square by 9-4 twice. But between (ii) and (iii) we find that
increase in square value would be 4-1 twice. Obviously the latter is less.
Well the real answer is three hundred-ninety three point five. So numbers around it could be three hundred and fifty and four hundred. An estimate could be three hundred and seventy five.
