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Vitek1552 [10]
3 years ago
8

G(b) = 5b- 9 h(b) = (b - 1)^2 Evaluate. (hog)(-6) =

Mathematics
1 answer:
laiz [17]3 years ago
7 0

Given:

The two functions are:

g(b)=5b-9

h(b)=(b-1)^2

To find:

The value of (h\circ g)(-6).

Solution:

We have,

g(b)=5b-9

h(b)=(b-1)^2

We know that,

(h\circ g)(b)=h(g(b))

(h\circ g)(b)=h(5b-9)

(h\circ g)(b)=[(5b-9)-1]^2

(h\circ g)(b)=[5b-10]^2

Putting b=-6, we get

(h\circ g)(-6)=[5(-6)-10]^2

(h\circ g)(-6)=[-39-10]^2

(h\circ g)(-6)=[-49]^2

(h\circ g)(-6)=2401

Therefore, the value of (h\circ g)(-6) is 2401.

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