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3 years ago

Help!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Vesnalui [34]3 years ago

6 0

Answer:

Step-by-step explanation:

it's the correct answer I'm sure of

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You are hiking in the woods at a rate of 3 mph. The function y=3x describes how many miles y you walk in x hours. create an inpu

Finger [1]

Answer:

x ---- y

1 ---- 3

4 ---- 12

6 ---- 18

Step-by-step explanation:

Given

$y = 3x$

Required

Create a table that represents this scenario

Because x represents time, x can not be negative. So, the domain of x is:

$x \geq 0$

Assume $x = 1$

$y = 3 * 1 = 3$

Assume x = 4

$y=3*4 = 12$

Assume x = 6

$y=3*6 = 18$

Hence, the table is:

x ---- y

1 ---- 3

4 ---- 12

6 ---- 18

4 0

3 years ago

Which equation has the same solutions as 4x + x - 5 = 0 ?

Lyrx [107]

5x-5=0
You simplify the left side

4 0

1 year ago

Read 2 more answers

15/16 divided by 20<br> 7/15 divided by 14

olga2289 [7]

Answer:

The first is 0.046 and the second is 0.033

Step-by-step explanation:

4 0

3 years ago

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

6 0

3 years ago

If the if a cylinder is 7 in tall and has a volume of 63 Pi inches what is the area of the cross section it goes right down the

vitfil [10]

Answer: $9\pi \ in.^2$

Step-by-step explanation:

Given

The height of the cylinder is $h=7\ in.$

The volume of the cylinder is $V=63\pi \ in.^3$

The volume of the cylinder is the product of area and height

$\Rightarrow V=\pi r^2h\\$

Insert the values

$\Rightarrow 63\pi =A\times 7\\\\\Rightarrow A=\dfrac{63\pi}{7}\\\\\Rightarrow A=9\pi\ in.^2$

Thus, the area of the cross-section is $9\pi \ in.^2$

7 0

2 years ago