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3 years ago

What is the measure of <6 <6=

Mathematics

1 answer:

givi [52]3 years ago

6 0

Answer:

20/20

Step-by-step explanation:

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A vender is loading candybars into a vending machine. Each slot holds 130cm of candy barsand each candy bar is 1.5cm thick, how

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

since the slot is 130 cm thick you divide that by the thickness of the candy bar 130/1.5 and then you get 86.6666666.....which rounds to 86 because the slot is not thick enough for another candy bar. good luck on whatever you needed this for!

8 0

3 years ago

How to find coordinates of a point using ratio

Marat540 [252]

m1=3, m2= 1

point A= (-5,4)

point B=(7,-2)

x=m1x2+m2x1/ m1+m2 , y=m1y2+m2y1 / m1+m2

x= 3×7 +1×-5/3+1 , y= 3×-2+1×4 / 3+1

x= 21-5/4, y= -6+4/4

x= 16/4, y= -2/4

x= 4, y= 0.5

5 0

3 years ago

given that p=(5,4),q=(7,3),r=(8,6) and s=(4,1) find the component form of the vector pq=3rs a.(-10,-16)b.(-6,4)c.(-2,-6)d.(14,14

Kitty [74]

Is it (-10, -16) i have that answer

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3 years ago

Convert and explain 28% to decimal and fraction

DaniilM [7]

28% as a decimal would be 0.28, since it is 28 out of 100, which answers the fraction question : 28/100

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4 years ago

Evaluate the interval (Calculus 2)

Darya [45]

Answer:

$2 \tan (6x)+2 \sec (6x)+\text{C}$

Step-by-step explanation:

<u>Fundamental Theorem of Calculus</u>

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}$

If the terms are multiplied by constants, take them outside the integral:

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x$

Multiply by the conjugate of 1 - sin(6x) :

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{1-\sin^2(6x)} \:\:\text{d}x$

$\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:$

$\implies \sin^2 (6x) + \cos^2 (6x)=1$

$\implies \cos^2 (6x)=1- \sin^2 (6x)$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

Expand:

$\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

$\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:$

$\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x$

$\implies 12\displaystyle \int \sec^2(6x)+\tan(6x)\sec(6x) \:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}$

$\boxed{\begin{minipage}{6 cm}\underline{Integrating $ \sec kx \tan kx$}\\\\$\displaystyle \int \sec kx \tan kx\:\text{d}x= \dfrac{1}{k}\sec kx\:\:(+\text{C})$\end{minipage}}$

$\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}$

Simplify:

$\implies \dfrac{12}{6} \tan (6x)+\dfrac{12}{6} \sec (6x)+\text{C}$

$\implies 2 \tan (6x)+2 \sec (6x)+\text{C}$

Learn more about indefinite integration here:

brainly.com/question/27805589

brainly.com/question/28155016

3 0

2 years ago