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patriot [66]
2 years ago
5

Which box plot correctly displays the data set with a maximum of 48, a minimum of 27, a median of 36, an upper quartile of 45, a

nd a lower quartile of 32?
(please refer to the answer like this: Image [number])

Mathematics
1 answer:
Vitek1552 [10]2 years ago
4 0

Answer:

Image 1

Step-by-step explanation:

To answer this question, we need to know how to use a box plot.

I've attached an image that demonstrates this well and can teach you what each part of the box plot means.

Specifically, the 2 farthest dots at the end are the minimum and maximum. The two sides where the box starts are the lower and upper quartiles. Finally, the line in the middle of the box is the median.

With this, we can analyze each box plot and determine which one is correct.

<em><u>Box Plot 1: </u></em><em>Everything is plotted correctly- Maximum and minimum plotted correctly, median plotted correctly, upper and lower quartile plotted correctly.</em>

<u>Box Plot 2:</u> Everything plotted correctly EXCEPT maximum of 48 is represented at 46.

<u>Box Plot 3:</u> Everything plotted correctly EXCEPT the upper quartile of 45 is at 39.

<u>Box Plot 4:</u> Upper quartile represented at 39 and maximum represented at 46 are both incorrect.

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3 years ago
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Airida [17]
Ok so remember that a circle is 360 degrees and a line is 180 degrees
so

IKJ
ok so we see that we have a triangle
to find the internal angles (which add to 180)
we do, opposite angles are equal
JIK=59
also CJI+KJI=180 so 132+KJI=180, KJI=48
so
59+48+IKJ=180
73=IKJ




HIB
we can assume that AB is paralell to CD
so therefor IJK=HIB=48 (from previous question)

EIJ is adding to EIH to get 180
EIJ+59=180
EIJ=121

AIK=AIJ+JIK
JIK=59
AIJ=HIB=48
AIK=59+48=107


IKJ=73
HIB=48
EIJ=121
AIK=107
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