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patriot [66]
2 years ago
5

Which box plot correctly displays the data set with a maximum of 48, a minimum of 27, a median of 36, an upper quartile of 45, a

nd a lower quartile of 32?
(please refer to the answer like this: Image [number])

Mathematics
1 answer:
Vitek1552 [10]2 years ago
4 0

Answer:

Image 1

Step-by-step explanation:

To answer this question, we need to know how to use a box plot.

I've attached an image that demonstrates this well and can teach you what each part of the box plot means.

Specifically, the 2 farthest dots at the end are the minimum and maximum. The two sides where the box starts are the lower and upper quartiles. Finally, the line in the middle of the box is the median.

With this, we can analyze each box plot and determine which one is correct.

<em><u>Box Plot 1: </u></em><em>Everything is plotted correctly- Maximum and minimum plotted correctly, median plotted correctly, upper and lower quartile plotted correctly.</em>

<u>Box Plot 2:</u> Everything plotted correctly EXCEPT maximum of 48 is represented at 46.

<u>Box Plot 3:</u> Everything plotted correctly EXCEPT the upper quartile of 45 is at 39.

<u>Box Plot 4:</u> Upper quartile represented at 39 and maximum represented at 46 are both incorrect.

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To solve this system of equations by elimination, what operation could be used to eliminate the x-variable and find the value of
stepan [7]

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

- 6x - 4y = 2 → (1)

- 4x - 7y = 2 → (2)

Multiplying (1) by 4 and (2) by - 6 will eliminate the x- term

- 24x - 16y = 8 → (3)

24x + 42y = - 12 → (4)

Add (3) and (4) term by term

26y = - 4 ( divide both sides by  26 )

y = \frac{-4}{26} = - \frac{2}{13}

7 0
3 years ago
Which values for A and B will create infinitely many solutions for this system of equations
Ratling [72]

Answer:

A = - 2 and B = - 8

Step-by-step explanation:

A = - 2 and B = - 8 will create infinitely many solutions for this system of equations

When you add both equations together and both sides are equal then the systems have infinitely many solutions

-2x - y = 8

2x + y = -8

--------------------Add

0 = 0

Both sides are equal 0

Infinitely many solutions

7 0
3 years ago
Is 7/45 a repeating or terminating
timurjin [86]

I believe that  7/45 is a repeating decimal

8 0
3 years ago
Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra
katen-ka-za [31]

You made a mistake with the probability p_{j}, which should be p_{i} in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer j, is given by:

(1) \frac{p_{j} }{1-d_{i}p_{i}  } , if j \neq i, and

(2) \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  } , if j = i.

so we can say:

A is the event that you search drawer i and find nothing,

B is the event that you search drawer i and find the paper,

C_{k}  is the event that the paper is in drawer k, k = 1, ..., n.

this gives us:

P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}

P(A) = 1 - P(B) = 1 - d_{i} p_{i}

Solution to Part (1):

if j \neq i, then P(A \cap C_{j} ) = P(C_{j} ),

this means that

P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)}  = \frac{P(C_{j} )}{P(A)}  = \frac{p_{j} }{1-d_{i}p_{i}  }

as needed so part one is solved.

Solution to Part(2):

so we have now that if j = i, we get that:

P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}

remember that:

P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}

this implies that:

P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )

so we just need to combine the above relations to get:

P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i}  }

as needed so part two is solved.

8 0
3 years ago
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steposvetlana [31]

Answer:

$58,45 or 5845 cents

Step-by-step explanation:

Weekly pay = 167 * 0.05 * 7 = $58.45 or 5845 cents

4 0
3 years ago
Read 2 more answers
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