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Nina [5.8K]
3 years ago
14

For which inequalities is 7 a solution?

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
7 0
The answer is c + 5 < 12
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The triangles are similar, solve for x.<br> N+3<br> 8
Nonamiya [84]

Answer:

5

Step-by-step explanation:

3+5=8

4 0
2 years ago
(03.01 LC)<br><br> What is the length of leg y of the right triangle? (1 point)
EastWind [94]

Answer:

<h2>A</h2>

Step-by-step explanation:

The complete question is

What is the length of leg y of the right triangle?

A right triangle with hypotenuse 26 and legs 24 and y

  • 10
  • 14
  • 24
  • 26

We need to use the Pythagorean Theorem, where h=26 and x=24,

h^{2} =x^{2} +y^{2}\\ 26^{2}=24^{2}+y^{2}\\y=\sqrt{26^{2}-24^{2}}\\ y=\sqrt{676-576}\\ y=\sqrt{100}\\ y=10

Therefore, the right answer is A. The length of the missing leg is 10 units.

4 0
3 years ago
PLEASE HELP QUESTION ATTACHED
Bess [88]
Point S is the answer 

move -2.25 on the x axis and 2/3 on the y form the origin

3 0
3 years ago
The price of a pair of shoes increases from $62 to $81. What is the percent increase to the nearest percent?
maksim [4K]
The answer is 30%






Because $62 + 30%= $80.6
4 0
3 years ago
Read 2 more answers
A 150 no container can hold 23.6 g of aluminum what is the density of the aluminum?
Drupady [299]

Answer:

# The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The volume of the container is 4/17 ≅ 0.235 cm³

# The mass of iron is 1225 g

Step-by-step explanation:

* Lets explain how to solve the problem

- Density is a measurement that compares the amount of matter

 of an object to its volume [ Density = mass/volume]

- Density is found by dividing the mass of an object by its volume

- The unit of measuring density is gram per centimeter³ (milliliter)

* Lets solve the problems

# A container of volume 150 cm³ can hold 23.6 g of aluminum

∵ Density = mass/volume

∵ The mass = 23.6 g

∵ The volume = 150 cm³

∴ The density = 23.6/150 = 59/375 ≅ 0.157 g/cm³

* The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The density of mercury is 13.6 g/cm³ at 23 C°

- A container can hold 3.2 g of mercury at this temperature

∵ Density = mass/volume

∵ The mass = 3.2 g

∵ The density = 13.6 g/cm³

∴ 13.6 = 3.2/volume

- By using cross multiplication

∴ The volume = 3.2/13.6 = 4/17 cm³

* The volume of the container is 4/17 ≅ 0.235 cm³

# The density of the iron is 4.9 g/cm³

- The beaker has a volume 250 ml

∵ Density = mass/volume

∵ The ml = cm³

∴ The volume of the beaker is 250 cm³

∵ The density = 4.9 g/cm³

∴ 4.9 = mass/250

- Multiply both sides by 250

∴ mass = 1225 g

* The mass of iron is 1225 g

7 0
3 years ago
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