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3 years ago

I will like to know how to solve this

Mathematics

1 answer:

Olenka [21]3 years ago

6 0

x = 2

Collect terms in x to one side of the equation and numeric values on the other side.

1 + 4x = - 5 + 7x ( subtract 7x from both sides )

1 + 4x - 7x = - 5

1 - 3x = - 5 ( subtract 1 from both sides )

- 3x = - 6 ( divide both sides by - 3 )

x = $\frac{- 6}{- 3}$ = 2

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Describe a sequence of transformations that can be performed to polygon ABCDE to prove that it is similar to polygon FGHIJ

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Answer:

answer below

Step-by-step explanation:

ABCDE go through dilation over center (6 , -2) with factor of 1/2 to FGHIJ

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2 years ago

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Answer:

Step-by-step explanation:

We can use the distance formula

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3 years ago

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Anna11 [10]

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3 years ago

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$

Therefore, we have;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$ .

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3 years ago

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Elena-2011 [213]

Answer: 1/25 or 0.04

Step-by-step explanation:

1/5 divided by 5 for the whole number you have to turn it to a fraction so you would do 5/1

THEN: it becomes 1/5 divided by 5/1 but you have to do the inverse so the inverse of division is multiplying and you will cross multiply so 5*5= 25 and 1*1=1 therefor the final answer is 1/25

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2 years ago

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