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Irina-Kira [14]
3 years ago
12

How much of a radioactive kind of xenon will be left after 15 days if the half-life is 5 days and

Mathematics
2 answers:
In-s [12.5K]3 years ago
7 0

Answer:

12 grams

Step-by-step explanation:

15/5 = 3 half lives

(1/2)³ = 1/8 of the original amount will remain

96 * 1/8 = 12 grams

Andrews [41]3 years ago
4 0

Answer:

Step-by-step explanation:

Radioactive decay problems are very similar to compound interest formulas, except the rate is subtracted from one, instead of adding to one.

I.e.

mass at time t, m(t) = M (1 - r)^(t/h)

where

M = initial mass (grams)

m (t) mass left at time t (grams)

h = half-life in number of days

r = 0.5 from "half-life"

t = time lapse in number of days

Here

M = 96

h = 5

t = 15

m(15) = 96(1-0.5)^(15/5)

= 96 (1/2)^3

= 12 grams

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Consider the vectors a =3i +j −k, b =i +j +4k, c=i +3j +k, d =−i −3j +k, g =−3i −j +k. Which pairs (if any) of these vectors are
11111nata11111 [884]

Answer:

a and b are perpendicular to each other, as are b and d, b and g

Step-by-step explanation:

To check whether two vectors are perpendicular to each other, we need the angle between these vectors to be 90 degrees.

We can find the angle between to vectors a and b from the following relation:

The cosine of the angle \theta between two vectors is equal to the dot product of this vectors divided by the product of vector magnitude.

So

cos(\theta) = \frac{a.b}{|a||b|}

cos(90) = 0, so when the dot product between vectors a and b is 0, it means that these vectors are perpendicular to each other.

Now, for your exercise, let's compute the dot product between these vectors.

-----------

a.b = (3,1,-1).(1,1,4) = 3+1-4 = 0

So a and b are perpendicular to each other.

------------

a.c = (3,1,-1).(1,3,1) = 3+3-1 = 5

a and c are not perpendicular to each other.

--------------

a.d = (3,1,-1).(-1,-3,1) = -3-3-1 = -7

So not perpendicular

---------------

a.g = (3,1,-1).(-3,-1,1) = -9-1-1 = -11

Not

-----------------

b.c = (1,1,4).(1,3,1) = 1+3+4 = 8

Not

------------------

b.d = (1,1,4).(-1,-3,1) = -1 -3 +4 = 0

b.d = 0, so b and d are perpendicular to each other

--------------------

b.g = (1,1,4).(-3,-1,1) = -3-1+4 = 0

b.g = 0, perpendicular

---------------------

c.d = (1,3,1).(-1,-3,1) = -1-9+1 = -9

No

-----------------------

c.g = (1,3,1).(-3,-1,1) = -3-3+1 = -5

No

------------------------

d.g = (-1,-3,1).(-3,-1,1) = 3+3+1 = 7

No

7 0
4 years ago
Point A is located at ​(4, 8)​ and point B is located at ​(14, 10)​ . What point partitions the directed line segment ​ AB⎯⎯⎯⎯⎯
andrew11 [14]

The 1:3 ratio means that the distance from A to the point is 1/4 of the distance from A to B.

The difference of y-coordinates is 10-8 = 2. 1/4 of that is 2·1/4 = 1/2, so the point of interest will have y-coordinate 8 + 1/2 = 8 1/2. This apparently corresponds to the first selection:

... (6 1/2, 8 1/2)

7 0
3 years ago
Last one i need help with these too
Licemer1 [7]
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5 0
3 years ago
Find two consecutive whole numbers such that 4/7 of the larger exceeds 1/2 of the smaller by 5
Darina [25.2K]

Answer:

The consecutive numbers are 62 and 63

Step-by-step explanation:

Let the larger number be represented by x and the smaller number by y,

Provided they are consecutive numbers;

x = y + 1 --- Equation 1

From the question; we have that

\frac{4x}{7} = \frac{y}{2} + 5 --- Equation 2

Required

Find x and y

Multiply both sides of equation 2 by 14

14 * \frac{4x}{7} = 14 * \frac{y}{2} + 14 * 5

2 * 4x = 7 * y + 70

8x = 7y + 70 ---- Equation 3

Substitute y + 1 for x in equation 2

8(y + 1) = 7y + 70

Open bracket

8y + 8 = 7y + 70

Collect like terms

8y - 7y = 70 - 8

y = 62

x = y + 1

So,

x = 62 + 1

x = 63

Hence, the consecutive numbers are 62 and 63

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3 years ago
Rectangle EFGH is rotated 90° clockwise around the origin. What are the coordinates of the image point F?
denpristay [2]

Answer:

3 -5 on edg

Step-by-step explanation:

4 0
3 years ago
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