Answer:
12 grams
Step-by-step explanation:
15/5 = 3 half lives
(1/2)³ = 1/8 of the original amount will remain
96 * 1/8 = 12 grams
Radioactive decay problems are very similar to compound interest formulas, except the rate is subtracted from one, instead of adding to one.
I.e.
mass at time t, m(t) = M (1 - r)^(t/h)
where
M = initial mass (grams)
m (t) mass left at time t (grams)
h = half-life in number of days
r = 0.5 from "half-life"
t = time lapse in number of days
Here
M = 96
h = 5
t = 15
m(15) = 96(1-0.5)^(15/5)
= 96 (1/2)^3
= 12 grams
Thank you
The first term of the AP i.e a = 33
and common difference i.e d = 28-33 = -5
So, 60th term = a +(n-1)d = a+ 59d
= 33 + 59( -5)
= 33- 295
= - 262
