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Dima020 [189]
3 years ago
11

Which country had control of Mali?ItalyGreat BritainSpainFrance

Mathematics
1 answer:
KatRina [158]3 years ago
6 0

Answer:

400

Step-by-step explanation:

if the train travel in 150miles in 3hr then\

150/3=50miles a hr

50 x 8 = 400 miles

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Food bill before tax $62 Sales tax: 8% Tip: 15%<br> What is the tax?
professor190 [17]
<h3>Answer:  $4.96</h3>

Work Shown:

8% = 8/100 = 0.08

8% of 62 = 0.08*62 = 4.96

8 0
2 years ago
Let S be the solid beneath z = 12xy^2 and above z = 0, over the rectangle [0, 1] × [0, 1]. Find the value of m &gt; 1 so that th
jonny [76]

Answer:

The answer is \sqrt{\frac{6}{5}}

Step-by-step explanation:

To calculate the volumen of the solid we solve the next double integral:

\int\limits^1_0\int\limits^1_0 {12xy^{2} } \, dxdy

Solving:

\int\limits^1_0 {12x} \, dx \int\limits^1_0 {y^{2} } \, dy

[6x^{2} ]{{1} \atop {0}} \right. * [\frac{y^{3}}{3}]{{1} \atop {0}} \right.

Replacing the limits:

6*\frac{1}{3} =2

The plane y=mx divides this volume in two equal parts. So volume of one part is 1.

Since m > 1, hence mx ≤ y ≤ 1, 0 ≤ x ≤ \frac{1}{m}

Solving the double integral with these new limits we have:

\int\limits^\frac{1}{m} _0\int\limits^{1}_{mx} {12xy^{2} } \, dxdy

This part is a little bit tricky so let's solve the integral first for dy:

\int\limits^\frac{1}{m}_0 [{12x \frac{y^{3}}{3}}]{{1} \atop {mx}} \right.\, dx =\int\limits^\frac{1}{m}_0 [{4x y^{3 }]{{1} \atop {mx}} \right.\, dx

Replacing the limits:

\int\limits^\frac{1}{m}_0 {4x(1-(mx)^{3} )\, dx =\int\limits^\frac{1}{m}_0 {4x-4x(m^{3} x^{3} )\, dx =\int\limits^\frac{1}{m}_0 ({4x-4m^{3} x^{4}) \, dx

Solving now for dx:

[{\frac{4x^{2}}{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right. = [{2x^{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right.

Replacing the limits:

\frac{2}{m^{2} }-\frac{4m^{3}\frac{1}{m^{5}}}{5} =\frac{2}{m^{2} }-\frac{4\frac{1}{m^{2}}}{5} \\ \frac{2}{m^{2} }-\frac{4}{5m^{2} }=\frac{10m^{2}-4m^{2} }{5m^{4}} \\ \frac{6m^{2} }{5m^{4}} =\frac{6}{5m^{2}}

As I mentioned before, this volume is equal to 1, hence:

\frac{6}{5m^{2}}=1\\m^{2} =\frac{6}{5} \\m=\sqrt{\frac{6}{5} }

3 0
2 years ago
(9·20+60)÷4−16+4·(20·5)
neonofarm [45]

\text {Hello! Let's Solve this Problem!}

\text {The First Step is to Solve the Parentheses:}

\text {90*20=180+60=240}\\\text {20*5=100}

\text {Your new Problem should be: 240/4-16+4+100}

\text {The Next Step is to Divide:}

\text {240/4=60}

\text {Your new Problem should be: 60-16+4*100}

\text {The Next Step is to Subtract:}

\text {60-16=44}

\text {Now the Next Step is to Multiply:}

\text {4*100=400}

\text {The Final Step is to Add:}

\text {44+100=}

\text {Your Answer should be:}

\fbox {444}

\text {Best of Luck!}

\text {-LimitedX}

6 0
3 years ago
Read 2 more answers
Please,slove the math step by step,Sir.
Nana76 [90]

Answer:

hi po gising pa po kayo

5 0
3 years ago
Use the formula V = s³, where V is the volume and s is the edge length of the cube, to solve this problem. A cube-shaped box has
aev [14]

Using the given equation and edge length:

V = 45^3

V = 45 x 45 x 45

V = 91,125 cubic meters

3 0
3 years ago
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