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3 years ago

In the figure below, DF is a straight line. What is the degree measure of <FEG?

Mathematics

1 answer:

Alexandra [31]3 years ago

7 0

Answer:

c. 56 degrees

Step-by-step explanation:

angle FEG and angle DEG add up to 180.

2x-6+3x-31=180

x=31

2(31)-6=56

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A spherical ball has a radius of 9 feet,What is the volume, in cubic feet, of the ball? Round your answer to the nearest hundred

Illusion [34]

Answer:

972pi

Step-by-step explanation

Equation of sphere volume = 4/3pir^3

4/3*9^3*pi = 972pi

6 0

3 years ago

a soft drink vendor at a popular beach analyzes his sales recods and finds that if he sells x cans of soda pop in one day, his p

ZanzabumX [31]

Complete Question:

A soft-drink vendor at a popular beach analyzes his sales records, and finds that if he sells x cans of soda pop in one day, his profit (in dollars) is given by P(x) = -0.001x² + 3x - 1800.

a. What is his maximum profit per day?

b. How many cans must be sold in order to obtain the maximum profit?

Answer:

a. $450

b. 1500 cans

Step-by-step explanation:

Given the following quadratic function;

P(x) = -0.001x² + 3x - 1800 ......equation 1

a. To find his maximum profit per day;

Since P(x) is a quadratic equation, P(x) would be maximum when $x = \frac {-b}{2a}$

Note : the standard form of a quadratic equation is ax² + bx + c = 0 ......equation 2

Comparing eqn 1 and eqn 2, we have;

a = -0.001, b = 3 and c = -1800

Now, we determine the maximum profit;

$x = \frac {-b}{2a}$

Substituting the values, we have;

$x = \frac {-3}{2*(-0.001)}$

Cancelling out the negative signs, we have;

$x = \frac {3}{2*0.001}$

$x = \frac {3}{0.002}$

x at maximum = 1500

Substituting the value of "x" into equation 1;

P(1500) = -0.001 * 1500² + 3(1500) - 1800

P(1500) = -0.001 * 2250000 + 4500 - 1800

P(1500) = -2250 + 2700

P(1500) = $450

b. Therefore, the soft-drink vendor must sell 1500 cans in order to obtain the maximum profit.

5 0

3 years ago

Helpppppppp me …………………..

grigory [225]

Answer:

first let's solve for x

x + (x + 30) + 2x = 180

4x + 30 = 180

-30 -30

4x = 150

/4 /4

x = 37.5

Now solve for the angle measures:

(x + 30) = (37.5 + 30) = 67.5

2x = 2(37.5) = 75

x = 37.5

7 0

2 years ago

Read 2 more answers

Please help, I don’t understand

IrinaK [193]

Using basic distance = speed x time, and rearranging it for speed as the subject...

5 0

4 years ago

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David’s bank offers a 36-month Certificate of Deposit (CD) with an APR of 2.25%. Use the compound interest formula to answer the

tamaranim1 [39]

Using compound interest, it is found that:

a) A(8) = 2389.66

b) t = 31.15

c) P = 1870.85

Compound interest:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

A(t) is the amount of money after t years.
P is the principal(the initial sum of money).
r is the interest rate(as a decimal value).
n is the number of times that interest is compounded per year.
t is the time in years for which the money is invested or borrowed.

In this problem:

The APR is of 2.25%, hence $r = 0.0225$ .

No information about the number of compounding per year, hence $n = 1$ .

Item a:

$P = 2000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$A(8) = 2000\left(1 + \frac{0.0225}{1}\right)^{8}$

$A(8) = 2389.66$

Item b:

$A(t) = 4000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$4000 = 2000\left(1 + \frac{0.0225}{1}\right)^{t}$

$(1.0225)^t = 2$

$\log{(1.0225)^t} = \log{2}$

$t\log{1.0225} = \log{2}$

$t = \frac{\log{2}}{\log{1.0225}}$

$t = 31.15$

Item c:

$A(3) = 2000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$2000 = P\left(1 + \frac{0.0225}{1}\right)^{3}$

$P = \frac{2000}{(1.0225)^3}$

$P = 1870.85$

A similar problem is given at brainly.com/question/24850750

7 0

2 years ago

In the figure below, DF is a straight line. What is the degree measure of <FEG?​

In the figure below, DF is a straight line. What is the degree measure of <FEG?