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tia_tia [17]
2 years ago
11

the exponent expression 2⁸ has a value of 256.write two other exponential expressions that have the value of 256. explain how yo

u got your answers
Mathematics
1 answer:
Flura [38]2 years ago
5 0

The other two expressions that have value of 256 is 4⁴ and 16².

Given the exponent expression 2⁸ has a value of 256.

We want to write two other exponential expressions that have value 256.

The given expression is 2⁸=256

The above expression can be written as

2×2×2×2×2×2×2×2=256

By using the Associative property of multiplication, we can write them as

(2×2)×(2×2)×(2×2)×(2×2)=256

4×4×4×4=256

4⁴=256

and it can also be written as by using the associative property of multiplication again and get

(2×2×2×2)×(2×2×2×2)=256

16×16=256

16²=256

Hence, the two other exponential expression of 256 other than 2⁸ is 4⁴ and 16².

Learn more about the exponential expression from here brainly.com/question/17003520

#SPJ9

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Answer:

\Huge \boxed{Z=84}

Step-by-step explanation:

To solve this problem, first you have to isolate it on one side of the equation. Remember to solve this problem, multiplication property of equality is multiply both sides of an equation the same number doesn't change the equation.

First, switch sides.

\displaystyle \frac{z}{14}=6

Next, multiply 14 from both sides.

\displaystyle \frac{14z}{14}=6*14

Solve.

\displaystyle 6*14=84

Therefore, the correct answer is z=84.

8 0
4 years ago
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Match the equation 3^4x-y=-3^4
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3 years ago
Use the diagram on the right. How many planes contain both the line and the point
Aloiza [94]

Part (a)

<h3>Answer: 0</h3>

-------------------

Explanation:

Point P is part of 3 planes or faces of this triangular prism:

  • plane PEF (the front slanted plane)
  • plane PEH (the left triangular face)
  • plane PHG (the back rectangular wall)

Notice how each three letter sequence involves "P", though this isn't technically always necessary. I did so to emphasize how point P is involved with these planes.

Each of the three planes mentioned do not involve line FG

  • Plane PEF only deals with point F
  • Plane PEH doesn't have any of F or G involved
  • plane PHG only involves G

So there are no planes that contain line FG and point P.

==================================================

Part (b)

<h3>Answer: 0</h3>

-------------------

Explanation:

It's the same idea as part (a) earlier. The planes involving point G are

  • plane GQF  (triangular face on the right)
  • plane GFE (bottom rectangular floor)
  • plane GHP (back rectangular wall)

None of these planes have line EP going through them.

As an alternative, we could reverse things and focus on all of the planes connected to line EP. Those 2 planes are

  • plane PEH (triangular face on the left)
  • plane PEF (front slanted rectangular face)

None of these planes have point G located in them.

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Alik [6]

Answer:

D

Step-by-step explanation:

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Answer:

for 1-12 I will say t (true) and f (false) to determine if it's proportional or not.

1) t.      7)t

2)t.      8)f

3)f.      9)t

4)t.      10)t

5)f.      11)t

6)f.      12)f

13) proportional

14) unproportional

6 0
3 years ago
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