Begin by factoring 2 out of 2x^2 - 2x - 12 equals 0:
2(x^2 - x - 6) = 0
2(x - 3)(x + 2) = 0. 2 is never zero, but x-3 and x+2 can each be set = to 0:
This results in x = 3 and x = -2. The equation is true for these two x-values.
Answer:
106ft by 2
Step-by-step explanation:
Simple
scientific notation
8.009 × 10-3
Answer:
1.A
2.B
3.A
4. D
5.C
Step-by-step explanation:
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Important: Use the symbol "^" to denote exponentiation:
<span>x3 – 9x2 + 5x – 45 NO
</span><span>x^3 – 9x^2 + 5x – 45 YES
Look at the first 2 terms. They can be rewritten as x^2(x-9). Then look at the last 2 terms. They can be rewritten as 5(x-9). So, x-9 is the common factor here. Thus, the original expression becomes:
(x^2-5)(x-9).
Note that x^2-5 can be factored, so that the final 3 factors are:
(x-sqrt(5)), (x+sqrt(5)), (x-9).</span>
