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astraxan [27]
3 years ago
11

Hank and Lynn are both paying off car loans. • Hank paid $2,000 upfront when he bought his car, and he pays $200 each month. • L

ynn did not pay any money upfront when she bought her car, and she pays $275 each month. Is the relationship between the number of months and the total amount paid proportionally for both Hank's and Lynn's loans?
Look at picture up above... Then here’s the real question

B. A graph that shows the number of months and the total amount paid by hank would
1. Not be a straight line
2. Be a straight line that passes through the origin
3. Be a straight line that does not pass through the origin

C. A graph shows the number of months and the total amount paid by Lynn would
1. Not be a straight line
2. Be a straight line that passes through the origin
3. Be a straight line that does not pass through the origin
D. The relationship between a number of months and the total amount paid is proportional for
1. Lynn’s loan only
2. Both loans
3. Hanks loans
4. Neither loan

Please answer B, C, and D
Mathematics
1 answer:
Mariana [72]3 years ago
4 0

Answer:

if you're doing the I-ready hope this help

Step-by-step explanation:

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On Halloween 4 friends each received 4⁄5 of a pound of candy. How much candy did they receive total?
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16/5 or 3 1/5

Step-by-step explanation:

Your equation would be 4/5*4 which equals 16/5

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16 with the remainder 2
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Find the slope (-8,10) (8,15)
Novosadov [1.4K]
<h3>Question:</h3>

find the slope (-8,10) (8,15)

<h3>Answer:</h3>

m = \frac{5}{16}

<h3>Step-by-step explanation:</h3>

Use the slope formula \frac{y2-y1}{x2-x1}

(x2,y1) = (-8,10) , (x2,y2) = (8,15)

m = \frac{15-10}{8-(-8)}

m = \frac{5}{16}

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7 0
3 years ago
In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a
nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ};

\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ};

\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q.

Also,

\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P in right triangle PBM.

Thus \rm \angle{P\hat{B}M} = \angle C\hat{M}Q.

Additionally \rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}.

Therefore \rm \triangle PBM \sim \triangle MCQ.

\rm \displaystyle BC = 2\;MC for M is the midpoint of segment BC.

\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC.

\rm \triangle PBM \sim \triangle MCQ implies that

\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3.

8 0
3 years ago
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