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user100 [1]
3 years ago
8

Stephen deposited $1800 into a savings account for which interest is compounded weekly at a rate of 3.2%. How much interest will

he earn after 10 years?
A. $58.51

B. $678.59

C. $2478.59

D. $7679.48
Mathematics
1 answer:
saveliy_v [14]3 years ago
7 0
I think the answer is D
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X ⋅ x ⋅ x ⋅ x ⋅ x = ? 5x x(x + 5) x + 5 x5
vampirchik [111]

Answer

x.x.x.x.x = 5x

Step-by-step explanation:

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3 years ago
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Match the term with the definition.
Bingel [31]

Answer:

A. Perpendicular Lines

B. Circle

C. Angle

D. Plane

E. Parallel Lines

Hope this helped! Mark as Brainliest Please! :)))

Step-by-step explanation:

8 0
3 years ago
Please help with the questions in the image
iren2701 [21]

Step-by-step explanation:

This seems to be calculus 1.

<u>Question a</u>

We have -2x^3 + 5x^2 + 9

m = slope = derivative

Find the derivative / slope of -2x^3 + 5x^2 + 9

We do this by differentiating the polynomials. There are a few methods to do this but I am going to use the power rule, which we multiply the constant by the exponent on the variable and subtract one from the exponent.

\frac{d}{dx}(-2x^3 + 5x^2 + 9)

-6x^2 + 10x

m = -6x^2 + 10x when x = a

<em>Now that we have this information, we can answer question b</em>

<u>Question b</u>

<u>The tangent line for Point (1, 12)</u>

First find the slope by using our derivative.

m = -6x^2 + 10x

m = -6(1)^2 + 10(1)

m = -6 + 10x

m = 4

Now that we have our slope, use point slope form to find our tangent line

y - 12 = 4(x - 1)

y(x) = 4x + 8


<u>Now lets do the same for the Point (2, 13)</u>

Find the slope at the point.

m = -6x^2 + 10x

m = -6(2)^2 + 10(2)

m = -24 + 10

m = -4

Now find the tangent line using point slope form of a line.

y(x) - 13 = -4(x - 2)

y(x) = -4x + 21


Now graph the lines, which I have done and you can see by viewing the image I have attached.


6 0
3 years ago
A dog chases a squirrel. The dog is originally 200 feet away from the squirrel. The dog's speed is 150 feet per minute. The squi
Dafna11 [192]

Answer:

15 seconds

Step-by-step explanation:

If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy:  the dog's rate is 150 and the squirrel's is 100.  The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know:  the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up.  Since we don't know what d is, we will just call it d!  Now it seems as though we have 2 unknowns which is a problem.  However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other.  Here's the dog's equation:

d = rt

d+200 = 150t

And the squirrel's:

d = 100t

If we solve both for t and set them equal to each other we have:

\frac{150}{d+200} =\frac{100}{d}

Now we can cross multiply to solve for d:

150d = 100d + 20,000 and

50d = 20,000

d = 400

But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took.  So sub that d value back into one of the equations we have solved for t and do the math:

t=\frac{100}{d}=\frac{100}{400} =\frac{1}{4}

That's 1/4 of a minute which is 15 seconds.

6 0
3 years ago
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(-3.7)to the power of 5
Nina [5.8K]

Answer:

-693.43957

Step-by-step explanation:

-3.7^5

6 0
3 years ago
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