Kerion had a beaded business.she can make 12 necklaces in 2 hours.how long will it take her to make 9 necklaces

Find mean, median and mode of 140, 130, 90, 80, 60, 50, 30, 20, 10, 0

Alecsey [184]

For the mean you would have to add up all the numbers up and divide by the amount of numbers. For your problem you would get 610/10= 61.

For the median you would arrange all the numbers in order from least to greatest and cancel one from the left and one from the right each time. Since there is no middle number, the closest would be 50 and 60. Thus you you add 50+60 and get 110 and then divide by 2 giving you 55.

For the mode, there is no mode because none of the numbers repeat more than once.

I hope this clarifies your doubt. :)

3 0

2 years ago

Se tiene un rectángulo cuya base mide el doble que su altura y su área es 12

irina [24]

Answer:

Part 1) The perimeter is $P=6\sqrt{6}\ cm$

Part 2) The diagonal is $d=\sqrt{30}\ cm$

Step-by-step explanation:

The question in English is

You have a rectangle whose base is twice the height and its area is 12

square centimeters. Calculate the perimeter of the rectangle and its diagonal

step 1

Find the dimensions of rectangle

we know that

The area of rectangle is equal to

$A=bh$

$A=12\ cm^2$

so

$bh=12$ ----> equation A

The base is twice the height

so

$b=2h$ ----> equation B

substitute equation B in equation A

$(2h)h=12\\2h^2=12\\h^2=6\\h=\sqrt{6}\ cm$

Find the value of b

$b=2\sqrt{6}\ cm$

step 2

Find the perimeter of rectangle

The perimeter is given by

$P=2(b+h)$

substitute

$P=2(2\sqrt{6}+\sqrt{6})\\P=6\sqrt{6}\ cm$

step 3

Find the diagonal of rectangle

Applying the Pythagorean Theorem

$d^2=b^2+h^2$

substitute

$d^2=(2\sqrt{6})^2+(\sqrt{6})^2$

$d^2=30$

$d=\sqrt{30}\ cm$

3 0

2 years ago

3^{x^{2}}=2^{\log_{3}2}\\find\:{3}^{x}

Rashid [163]

Answer:

b r u h what

Step-by-step explanation:

6 0

2 years ago

Tell whether the equation has one, zero, or infinitely many solutions: 9(x - 4) +15=9x – 21

Mama L [17]

Answer:

Infinite solutions

Step-by-step explanation:

Simplify both sides, subtract 9x, and add 21x to both sides and you will get 0 = 0 so there is infinite solutions.

8 0

2 years ago

What is the solution to the system of equations graphed below

madreJ [45]

$\underline{+\left\{\begin{array}{ccc}y=-x-1\\y=x+1\end{array}\right}\ \ \ \ |\text{add both sides}\\\\.\ \ \ \ \ 2y=0\ \ \ |:2\\.\ \ \ \ \ y=0\\\\\text{substitute the value of y to the second equation}\\\\0=x+1\ \ \ \ |-1\\x=-1\\\\Answer:\ A.\ (-1,\ 0)$

8 0

2 years ago