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denpristay [2]
3 years ago
6

Lourdes vendió 2/5 partes de terreno de cultivo y sembró zanahorias en 2/3 partes del terreno restante ¿que parte del terreno or

iginal se utilizó para sembrar con zanahorias ?
Mathematics
1 answer:
Marina86 [1]3 years ago
3 0

Respuesta: 2/5

Explicación paso a paso:

Dado que :

Fracción de tierras agrícolas vendidas = 2/5

Fracción restante = 1 - 2/5 = (5 - 2) / 5 = 3/5

Fracción del resto utilizado para plantar zanahorias = 2/3

Por lo tanto, parte de la tierra original utilizada para plantar zanahoria será:

2/3 de la fracción restante después de la venta

2/3 de 3/5

2/3 * 3/5 = 6/15 = 2/5

Por lo tanto, parte de la tierra original utilizada para plantar zanahorias es 2/5

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Answer:

x=10.5

Step-by-step explanation:

if the two triangles were ratios it would be like

19.3:7.2 to x:3.9

so 75.27 = 7.2x

whcih is 10.45 which is approximately 10.5

8 0
2 years ago
If Clay can run one lap in a ¼ of an hour. How many hours will it take him to run 5 ⅓ laps around the track.​
Serjik [45]

Answer: 21

Step-by-step explanation

5 1/4 divided by 1/4

u simplify 5 1/4 =21/4

1/4=0.25

21/4 divided by 1/4 is 21

4 0
3 years ago
Help ASAP please !! No scam I really need this<br> Trigonometry!!
USPshnik [31]
<h3>Answer:  Choice D)  7.5 cm</h3>

==========================================================

Explanation:

We are told that quadrilateral ABCD is similar to quadrilateral EFGH.

The order of the four letter sequence is important.

  • For ABCD, we have AB as the first pair of letters.
  • For EFGH, we have EF as the first pair of letters.

Therefore, AB and EF are corresponding sides.

So AB = 10 and EF = x pair up together. We can form the ratio AB/EF which becomes 10/x.

The diagram shows that AD = 8. Notice that A and D are the first and last letters of ABCD. The first and last letters of EFGH are E and H. We can see that AD and EH correspond to one another because of this.

AD = 8 and EH = 6 forming the ratio AD/EH = 8/6

Because the quadrilaterals are similar, the corresponding ratios must be the same. Therefore, AB/EF is the same as AD/EH.

-----------------------

Let's set up a proportion to solve for x

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6 0
3 years ago
A+2/a-5÷a+1/a2-8a+15
krok68 [10]
For A+\frac{2}{a}-\frac{5}{a}+\frac{1}{a^2}-8a+15

Combine the fractions \frac{2}{a}  -  \frac{5}{a} \ \textgreater \  \mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \  \frac{2-5}{a}


\mathrm{Subtract\:the\:numbers:}\:2-5=-3 \ \textgreater \  \frac{-3}{a}

\mathrm{Apply\:the\:fraction\:rule}:\ \frac{-a}{b}=-\frac{a}{b} \ \textgreater \  -\frac{3}{a}

Therefore our final answer is A-\frac{3}{a}+\frac{1}{a^2}-8a+15

Hope this helps!
3 0
3 years ago
What’s the answer need help
e-lub [12.9K]

Answer:

D. last option

Step-by-step explanation:

distribute the exponents outside of parentheses to terms in side to get

x^10 y^20 z^5 on top

and x^2 y^2

then you can subtract the exponents of like terms from numerator and denominator to get

x^8 y^18 z^5

5 0
3 years ago
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