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Zolol [24]
3 years ago
11

Drag numbers to use a negative factor to factor the expression –5g + 15h – 25. Numbers may be used once, more than once, or not

at all.
–1 –2 –3 –4 –5 1 2 3 4 5
(_____g –_____ h +_____)
Mathematics
1 answer:
Gala2k [10]3 years ago
6 0

Answer:

(5g –15h +25)

hope dis helps ^-^

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There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,
lys-0071 [83]

<h2 /><h2>Here we go ~ </h2>

According to given information there are :

  • 5 red balls

  • 4 blue balls

  • 6 yellow balls

  • 10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

-

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{total \: red \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{25}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{1}{5}

<h3>2. what is the probability that the ball chosen is blue ?</h3>

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{total \: blue \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{25}

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{total \: yellow\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{25}

<h3>4. what is the probability that the ball chosen is green ?</h3>

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{total \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{25}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{2}{5}

<h3>5. what is the probability that the ball chosen is not green ?</h3>

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{total \: non \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{15}{25}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{3}{5}

3 0
2 years ago
What are the odds of rolling 2 dice and getting the sum of 7?
Yuliya22 [10]

Answer:

1/6

Step-by-step explanation:

favorable over total outcomes

favorable is 6

total is 36

6/36 = 1/6

6 favorable outcomes are:

(1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }

total of 36 outcomes are :

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6),

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6),

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6),

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6),

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

testbookcom

quora Praneethreddy Ravi Shetye

5 0
2 years ago
I need help with three and four
mart [117]

Answer:

3: a^{2}+2ab+b^{2}

4: 8x^{3} -12x^{2}+6x-1

Step-by-step explanation:

Question 3 can be re-written as:

(a+b)(a+b)

which equals:

a^{2}+2ab+b^{2}

Question 4 can be re-written as:

(2x-1)(2x-1)(2x-1)

Doing the first 2 brackets gives us:

(4x^{2} -4x+1)(2x-1)

Expanding these two:

8x^{3} -4x^{2} -8x^{2} +4x+2x-1

Simplifying it:

8x^{3} -12x^{2}+6x-1

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Find the value of the 100th and 1000th term in the sequence { 3,-5,7,-9,...}
pogonyaev
The value of 100th is 201
and the value of 1000th is 2001
7 0
2 years ago
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