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uysha [10]
3 years ago
15

A dozen donuts cost $4.20. How much will 1 donut cost?

Mathematics
2 answers:
CaHeK987 [17]3 years ago
5 0
$0.35 is the answer yea brainly forcing me to make it at least 20 characters.
melisa1 [442]3 years ago
3 0
You divide $4.20 by a dozen (12).
This gives you $0.35 per donut

For the next one, you divide $7 by 4 to get the individual price. This gives you $1.75 per cookie, but you still need to multiply it by 9 to get the total price of 9 cookies.
When you multiply 9 by 1.75, your final answer for the second one is $15.75.
Hope this helps :)
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Easy volume problem.
bagirrra123 [75]

Volume = l×b×h = 48×40×30 = 57600 cm²

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3 years ago
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A study investigating the relationship between age and annual medical expenses randomly samples 400 individuals in a city. It is
ICE Princess25 [194]

Answer:

The probability is 0.789

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\sigma = 16, n = 400, s = \frac{16}{\sqrt{400}} = 0.8

Find the probability that the mean age of the individuals sampled is within one year of the mean age for all individuals in the city.​

Using \mu = 30, this is the pvalue of Z when X = 31 subtracted by the pvalue of Z when X = 29. So

X = 31

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{31 - 30}{0.8}

Z = 1.25

Z = 1.25 has a pvalue of 0.8944

X = 29

Z = \frac{X - \mu}{s}

Z = \frac{29 - 30}{0.8}

Z = -1.25

Z = -1.25 has a pvalue of 0.1056

0.8944 - 0.1056 = 0.7888

Rounded to three decimal places, 0.789

The probability is 0.789

4 0
3 years ago
Read 2 more answers
How much can 0.75 go into 4.5
Nutka1998 [239]

Answer:

6 times

Step-by-step explanation:

well  just divide 4.5 by 0.75 to get

8 0
3 years ago
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What is m∠V?
Bezzdna [24]
We know that
Applying the law of cosines

c²=a²+b²-2*a*b*cos C------> cos C=[a²+b²-c²]/[2*a*b]

in this problem

a=7.6 in

b=8.6 in

c=7.4 in

C=angle V

 cos C=[7.6²+8.6²-7.4²]/[2*7.6*8.6]----> 0.5887

C=arc cos (0.5887)--------> C=53.93°-------> C=53.9°


the answer is

angle V is 53.9°


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3 years ago
-588298÷239<br><br> This is real homework please help me out...
klio [65]
-588298 divided by 239 equals 2461.49791
7 0
3 years ago
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