Which value of k makes the equation k2=10k2=10 true?20 20 12 8 5

What is the slope of the line described by the equation below?

postnew [5]

Answer: 4

Step-by-step explanation: First convert the equation to y = mx + b form.

Start by subtract 4x from both sides to get -y = -4x + 3.

From here, divide both sides by -1 to get y = 4x - 3.

Now in y = mx + b form, the slope is the multiplier, or the m.

So here, 4 is the slope.

5 0

3 years ago

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What is 275x56 in stander algorithm pls help

leonid [27]

1650
1375
15400
Hope this will be helpful

5 0

3 years ago

Triangle ABC is reflected across the y-axis to form the image A'B'C'. Triangle A'B'C' is then reflected across the x-axis to for

Anestetic [448]

Answer:

Circular!

Step-by-step explanation:

Triangle ABC is reflected across the y-axis to form the image A'B'C'. Triangle A'B'C' is then reflected across the x-axis to form the image A''B''C''. What type of rotation can be used to describe the relationship between triangle A"B"C" and triangle ABC

3 0

3 years ago

In a ∆ABC , angle A + Angle B = 125° and Angle B + Angle C = 150° . Find all the angles of ∆ABC.

mel-nik [20]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle ABC

$\purple{\rm :\longmapsto\:\angle A + \angle B = 125 \degree \: - - - (1) }$

$\purple{\rm :\longmapsto\:\angle B + \angle C = 150 \degree \: - - - (2)}$

We know,

Sum of all interior angles of a triangle is supplementary.

$\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C = 180\degree }$

On adding equation (1) and (2), we get 

$\purple{\rm :\longmapsto\:\angle A + \angle B + \angle B + \angle C = 125\degree + 150 \degree \:}$

$\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C + \angle B = 275\degree \:}$

$\purple{\rm :\longmapsto\:180\degree + \angle B = 275\degree \:}$

$\purple{\rm :\longmapsto\:\angle B = 275\degree - 180\degree \:}$

$\purple{\rm :\longmapsto\:\angle B = 95\degree \:}$

On substituting the value in equation (1) and (2), we get

$\purple{\rm :\longmapsto\:\angle A + 95\degree = 125\degree }$

$\purple{\rm :\longmapsto\:\angle A = 125\degree - 95\degree }$

$\purple{\rm :\longmapsto\:\angle A = 30\degree }$

Also, from equation (2), we get

$\purple{\rm :\longmapsto\:95\degree + \angle C = 150\degree }$

$\purple{\rm :\longmapsto\:\angle C = 150\degree - 95\degree }$

$\purple{\rm :\longmapsto\:\angle C = 55\degree }$

Hence,

$\begin{gathered}\begin{gathered}\bf\: \rm\implies \:\begin{cases} &\sf{\angle A = 30\degree } \\ \\ &\sf{\angle B = 95\degree } \\ \\ &\sf{\angle C = 55\degree } \end{cases}\end{gathered}\end{gathered}$

3 0

3 years ago

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Point O is the center of the circle. Circle O is shown. Tangents D C and B C intersect at point C outside of the circle. Lines a

azamat

Answer:

The perimeter is 28 (6 plus 8=14 14x2= 28)

Step-by-step explanation:

Plz mark brainliest!

5 0

3 years ago

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