2 years ago

Find DE. F) 3 G) 6 H) 9 J) 12

1 answer:

6 0

Answer:

Step-by-step explanation:

F because im guessing and im taking a tes

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Answer:

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Zarrin [17]

All these given roots are contained in option C.

The given equation is :

$9x^{3}+9x^{2}-4x-4=0$

$9x^{2}(x+1)-4(x+1)=0$

$(9x^{2}-4)(x+1)=0$

$9x^{2}-4=0,x+1=0$

$x^{2}=\frac{4}{9},x=-1$

$x=\frac{2}{3},x=-1$

Roots = $-1,\frac{-2}{3} ,\frac{2}{3}$

Hence these lie in between $(\frac{-3}{2} ,\frac{3}{2})$

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Stolb23 [73]

Answer:

it would be

B. y + 5 = 2(x + 6)

if there is a negative number and you are subtracting it turns positive

Step-by-step explanation:

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3 years ago