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3 years ago

Three integers have a mean of 7, a median of 5 and a range of 14. find the three integers

Mathematics

1 answer:

inna [77]3 years ago

4 0

Answer:

1, 5, 15

Step-by-step explanation:

First, I knew 5 was one of them because, 5 was the median and there were only three numbers. Next you have to find out the first and last number. Then, I looked at the mean. To get the mean, you have to add all of the numbers up and divide that by how many numbers there are. Since the mean is 7 and there are 3 numbers, I knew that the sum of all three numbers was 21 because, 21 divided by 3 is 7. Then I saw that the range of all the numbers was 14. The range is the difference between the largest and smallest number so I knew that the largest number subtracted by the smallest number had to be 14. Then, I saw that 15-1=14, and 1+5+15=21. So the three integers are, 1, 5 and 15.

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Which of the following values of x make the following functions equal? y = 2x + 6 and

Papessa [141]

Answer:

the answers Is c. x=4

Step-by-step explanation:

do substitution 2*4+6=14

and 6*4-10=14

6 0

2 years ago

Billy did a survey to answer the following question:

kogti [31]

Answer:

7.8

Step-by-step explanation:

Since the average is 7.8 and everyone scored the same score so

that means everyone scored a 7.8

4 0

3 years ago

Let point L be between M and N on MN. Given that MN=31, ML= h-15 and LN = 2h-8. Find LN

MrRa [10]

Since the distance of MN is 31 and we have a distance of ML of h -15 and LN of 2h – 8, therefore

ML + LN = h -15 + 2h – 8 = 31

h = 18

substituting the value of h to the expression for LN obtaining

LN = 2h – 8

LN = 2(18) – 8

LN = 28

Therefore the length of the segment LN is 28 units

7 0

3 years ago

La ecuación de la recta que pasa por los puntos (2,-1) y (1,-5) es:

77julia77 [94]

Given:

A line passes through the points (2,-1) and (1,-5).

To find:

The equation of the line.

Solution:

If a line passes through the two points, then the equation of the line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

The line passes through the points (2,-1) and (1,-5). So, the equation of the line is

$y-(-1)=\dfrac{-5-(-1)}{1-2}(x-2)$

$y+1=\dfrac{-5+1}{-1}(x-2)$

$y+1=\dfrac{-4}{-1}(x-2)$

$y+1=4(x-2)$

Using distributive property, we get

$y+1=4(x)+4(-2)$

$y+1=4x-8$

Subtract 1 from both sides.

$y+1-1=4x-8-1$

$y=4x-9$

Therefore, the correct option is B.

5 0

3 years ago

A colony of bacteria is grown under ideal conditions in a laboratory so that the population increases exponentially with time. A

Naddik [55]

Answer:

Initial bacterias = 6006000

Altought I believe is safe to assume that the values were 192,000 and 384,000 instead of 192,192,000 and 384,384,000, in that case the initial bacterias is 6000

Step-by-step explanation:

A exponential growth follows this formula:

Bacterias = C*rⁿ

C the initial amount

r the growth rate

n the number of time intervals

Bacterias (55 hours) = 192,192,000

Bacterias (66 hours) = 384,384,000

$Bacterias(55hours)=C*r^{{\frac{55-t}{t}}} \\Bacterias (66hours) = C*r^{\frac{66-t}{t}}}$

If you divide both you can get the growth rate:

$\frac{Bacterias (66hours)}{Bacterias(55hours)}=\frac{C*r^{\frac{66-t}{t}}}{C*r^{{\frac{55-t}{t}}}} \\\frac{384,384,000}{192,192,000} =r^{\frac{66-t}{t} -\frac{55-t}{t} } \\2 =r^{\frac{11}{t}}$

So with that r = 2 and each time interval correspond to 11 years

Then replacing in one you can get the initial amount of C

$Bacterias (55hours)=C*2^{\frac{55-11}{11} } 192,192,000 = C*32\\C= 6006000$

7 0

3 years ago

Three integers have a mean of 7, a median of 5 and a range of 14. find the three integers​

Three integers have a mean of 7, a median of 5 and a range of 14. find the three integers