well, we know that 1ft³ = 7.48 gallons, alright, we have a volume in gallons and a diameter in feet, so if we were to use the diameter in feet to get the volume what we would end up will be a volume in ft³, so let's convert firstly the gallons to ft³ then
![750g\cdot \cfrac{ft^3}{7.48g}\implies 750g\cdot \cfrac{ft^3}{~~\frac{748}{100}g~~}\implies \cfrac{18750}{187}ft^3](https://tex.z-dn.net/?f=750g%5Ccdot%20%5Ccfrac%7Bft%5E3%7D%7B7.48g%7D%5Cimplies%20750g%5Ccdot%20%5Ccfrac%7Bft%5E3%7D%7B~~%5Cfrac%7B748%7D%7B100%7Dg~~%7D%5Cimplies%20%5Ccfrac%7B18750%7D%7B187%7Dft%5E3)
why do I use a fraction? for the sake of not losing value in the rounding, so let's use the fraction for the volume of a right-circular cylinder
![\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} h=height\\ r=radius\\[-0.5em] \hrulefill\\ r = \stackrel{\textit{half diameter}}{2}\\ V=\frac{18750}{187} \end{cases}\implies \cfrac{18750}{187}=\pi (2)^2h \\\\\\ \cfrac{18750}{187(4\pi )}=h\implies \stackrel{ft}{7.979}~\approx~h\implies \stackrel{\textit{converting to inches}}{7.979\cdot 12\approx h}\implies \stackrel{\textit{rounded up}}{\stackrel{in}{96}\approx h}](https://tex.z-dn.net/?f=%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%5C%5C%5C%5C%20V%3D%5Cpi%20r%5E2%20h~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%20%3D%20%5Cstackrel%7B%5Ctextit%7Bhalf%20diameter%7D%7D%7B2%7D%5C%5C%20V%3D%5Cfrac%7B18750%7D%7B187%7D%20%5Cend%7Bcases%7D%5Cimplies%20%5Ccfrac%7B18750%7D%7B187%7D%3D%5Cpi%20%282%29%5E2h%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B18750%7D%7B187%284%5Cpi%20%29%7D%3Dh%5Cimplies%20%5Cstackrel%7Bft%7D%7B7.979%7D~%5Capprox~h%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bconverting%20to%20inches%7D%7D%7B7.979%5Ccdot%2012%5Capprox%20h%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Brounded%20up%7D%7D%7B%5Cstackrel%7Bin%7D%7B96%7D%5Capprox%20h%7D)
Answer:
x = 10
Step-by-step explanation:
9x + 9 = 8x + 19
9x - 8x = 19 -9
x =10
The correct answer for this question is this one: "B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power"
<span>A. 5 times the quotient 5 cubed over two-fifths, raised to the second power
B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power
C. 5 to the negative 2 over 5 to the negative 5
E. 5 times the quotient 5 to the 5 over 5 cubed</span>