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kicyunya [14]
3 years ago
5

PLS HELP ASAP!! which of these would be easier to do in a database program than a spreadsheet program? check all of the boxes th

at apply.
• Store a list of favorite books for personal use
• email all customers who purchased a laptop the previous year
• perform complex calculations
• collect and analyze survey results
• update the record with ID#5872033
Computers and Technology
2 answers:
Contact [7]3 years ago
8 0

Answer:

a,b

Explanation:

REY [17]3 years ago
3 0

Answer:

It's B,D,E

Explanation:

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Light travels at 3 × 108 meters per second. A light-year is the distance a light beam travels in one year.Write a PYTHON program
Volgvan

Answer: This is a python code

def lightyear():

   rate=3*100000000   //speed of light

   seconds=365*24*60*60   //number of seconds in 1 year

   return str((rate*seconds)/1000)+" km"    //distance=speed x time

print(lightyear()) //will print value of light hear in kilometers

OUTPUT :

9460800000000.0 km

Explanation:

In the above code, there is a variable rate, which stores the speed of light, i.e. distance traveled by light in 1 second which is in meters. Another variable is seconds, which store the number of seconds in 1 year, which is no of days in 1 year multiplied by the number of hours in a day multiplied by the number of minutes in an hour multiplied by the number of seconds in a minute. Finally, distance is speed multiplied by time, so distance is printed in kilometers and to convert distance in kilometers it is divided by 1000.

4 0
3 years ago
Find the propagation delay for a signal traversing the in a metropolitan area through 200 km, at the speed of light in cable (2.
Ede4ka [16]

Answer:

t= 8.7*10⁻⁴ sec.

Explanation:

If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.

As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.

Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

v = \frac{(xf-xo)}{(t-to)}

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

t =\frac{xf}{v}  =\frac{2e5 m}{2.3e8 m/s} =8.7e-4 sec.

⇒ t = 8.7*10⁻⁴ sec.

4 0
3 years ago
Algorithm that has been coded into something that can be run by a machine.
hram777 [196]
The answer is program
8 0
3 years ago
Difference between server and a client computer
maw [93]

Answer:

A server stores data for a client computer to access and use, and pretty self eplanitory for a client computer

Explanation:

5 0
3 years ago
Do people answer questions more on this site or be on social more ??? no right or wrong answer your opinion
Sindrei [870]
It really depends on the person
3 0
3 years ago
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