The answer is:
You can use one budget to advertise on the Search Network and Display Network
Answer:
double arrow shape
Explanation:
To adjust the height of the cells
1. We have to position the mouse pointer over one of the column line or the one of the row line.
2. As we place the pointer between the dividing lines, the cursor of the mouse pointer change from singe bold arrow to double arrow symbol.
3.Now press or click the left mouse button and drag the dividing lines of the cells to the desired position to have the required width or height of the cell.
No.... This wont happen.... The computer only renames the file and dont let those apps go....in easy words We can say that the comp tells the apps to stay here...
Here is my solution. I did the following:
- changed the setRemover into a constructor, since the comment seems to hint that that is expected.
- changed the lookFor type into a String, so that it can work with the string replace overload. That's convenient if you want to replace with an emtpy string. The char type won't let you do that, you can then only replace one char with another.
- Added a static Main routine to use the class.
import java.lang.System.*;
public class LetterRemover
{
private String sentence;
private String lookFor;
public LetterRemover() {}
// Constructor
public LetterRemover(String s, char rem)
{
sentence = s;
lookFor = String.valueOf(rem);
}
public String removeLetters()
{
String cleaned = sentence.replace(lookFor, "");
return cleaned;
}
public String toString()
{
return sentence + " - letter to remove " + lookFor;
}
public static void main(String[] args)
{
LetterRemover lr = new LetterRemover("This is the tester line.", 'e');
System.out.println(lr.toString());
String result = lr.removeLetters();
System.out.println("Resulting string: "+result);
}
}
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int minn=INT_MAX;
int maxx=INT_MIN;
int n1,n2,n3,n4,n5;
cout<<"enter five Numbers:";
//read 5 Numbers
cin>>n1>>n2>>n3>>n4>>n5;
// find maximum
if(n1>maxx)
maxx=n1;
if(n2>maxx)
maxx=n2;
if(n3>maxx)
maxx=n3;
if(n4>maxx)
maxx=n4;
if(n5>maxx)
maxx=n5;
// find minimum
if(n1<minn)
minn=n1;
if(n2<minn)
minn=n2;
if(n3<minn)
minn=n3;
if(n4<minn)
minn=n4;
if(n5<minn)
minn=n5;
// print maximum and minimum
cout<<"maximum of five numbers is: "<<maxx<<endl;
cout<<"minimum of five numbers is: "<<minn<<endl;
return 0;
}
Explanation:
Declare two variables "minn" & "maxx" and initialize them with INT_MAX and INT_MIN respectively.Then read the five number from user and compare it with "minn" & "maxx" ,if input is greater than "maxx" then update "maxx" or if input is less than "minn" then update the "minn". After all the inputs, "minn" will have smallest and "maxx" will have largest value.
enter five Numbers:5 78 43 55 12
maximum of five numbers is: 78
minimum of five numbers is: 5
