FOR 20 POINTS: What expression is represented in the model shown below?

The number of responses to a survey are shown in the Pareto chart. The survey asked 1052 adults how they would grade the quality

Goryan [66]

Answer: (a) P(no A) = 0.935

(b) P(A and B and C) = 0.0005

(c) P(D or F) = 0.379

(d) P(A or B) = 0.31

Step-by-step explanation: Pareto Chart demonstrates a relationship between two quantities, in a way that a relative change in one results in a change in the other.

The Pareto chart below shows the number of people and which category they qualified each public school.

(a) The probability of a person not giving an A is the difference between total probability (1) and probability of giving an A:

P(no A) = $1-\frac{68}{1052}$

P(no A) = 1 - 0.065

P(no A) = 0.935

b) Probability of a grade better than D, is the product of the probabilities of an A, an B and an C:

P(A and B and C) = $(\frac{68}{1052})(\frac{258}{1052})(\frac{327}{1052})$

P(A and B and C) = $\frac{5736888}{1164252608}$

P(A and B and C) = 0.0005

c) Probability of an D or an F is the sum of probabilities of an D and of an F:

P(D or F) = $\frac{269}{1052} +\frac{130}{1052}$

P(D or F) = $\frac{399}{1052}$

P(D or F) = 0.379

d) Probability of an A or B is also the sum of probabilities of an A and of an B:

P(A or B) = $\frac{68}{1052} +\frac{258}{1052}$

P(A or B) = $\frac{326}{1052}$

P(A or B) = 0.31

7 0

3 years ago

A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p

Oliga [24]

Answer:

no of sample within two percentage points is 5409

no of sample not use prior estimates is 8321

Step-by-step explanation:

Given data

E = 2% = 0.02

male m = 21.2 % = 0.212

female f = 19.7 % = 0.197

to find out

no of sample within two percentage points and if does not use any prior estimates

solution

first we calculate no of sample within two percentage points

we know Z critical value for 99% is 2.58

so no of sample will be

n = (Z / E )² × m(1-m) + f ( 1-f )

put all the value we get no of sample

n = (2.58 / 0.02 )² × 0.212 ( 1 - 0.212 ) + 0.197 ( 1 - 0.197 )

n = 16641 ×0.3250

no of sample within two percentage points is 5409

in 2nd part no of sample not use prior estimates

here than f and m will be 0.5

than

n = (Z / E )² × m(1-m) + f ( 1-f )

put all value

n = (2.58 / 0.02 )² × 0.5 ( 1 - 0.5 ) + 0.5 ( 1 - 0.5 )

n = 16641 × 0.5

no of sample not use prior estimates is 8321

7 0

3 years ago

The reflection of a Quadrant II point is located in Quadrant I. Assuming no error was made, what kind of reflection occurred?

gizmo_the_mogwai [7]

Answer:

A reflection across the y- axis

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y) → (-x, y)

A point in the second quadrant (- x, y)

Under reflection in the y- axis is (x, y) ← point in first quadrant

3 0

3 years ago

Read 2 more answers

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$