10 points!!HELPP ME PLEASE ❗️❗️4. Figure HJKL

-_- i hate khan plz help me

agasfer [191]

Answer:

Dis’ old bet you got help lolllllllllllllll *sings in gay ferret*

I might be better on my own

I hate you blowing up my phone

I wish I never met yo' a*s

Sometimes it be like that

But I'm not myself the nights you're gone

There ain't no way I'm moving on

I'm not afraid to need you bad

Sometimes it be like that

8 0

3 years ago

What is 0.774193 rounded to the nearest tenth

Damm [24]

Rounded to the nearest tenth would be 0.8

3 0

3 years ago

Read 2 more answers

Pluto's distance P(t)P(t)P, left parenthesis, t, right parenthesis (in billions of kilometers) from the sun as a function of tim

Xelga [282]

Answer: P(t) = 1.25.sin( $\frac{\pi}{3}$ .t) + 5.65

Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:

y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D

where:

A is amplitude A=|A|

B is related to the period by: T = $\frac{2.\pi}{B}$

C is the phase shift or horizontal shift: $\frac{C}{B}$

D is the vertical shift

In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.

Amplitude:

a = $\frac{largest - smallest}{2}$

At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:

a = $\frac{6.9-4.4}{2}$

a = 1.25

b

A time period for Pluto is T=66 years:

66 = $\frac{2.\pi}{b}$

b = $\frac{\pi}{33}$

Vertical Shift

It can be calculated as:

d = $\frac{largest+smallest}{2}$

d = $\frac{6.9+4.4}{2}$

d = 5.65

Knowing a, b and d, substitute in the equivalent positions and find P(t).

P(t) = a.sin(b.t) + d

P(t) = 1.25.sin( $\frac{\pi}{3}$ .t) + 5.65

The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin( $\frac{\pi}{3}$ .t) + 5.65

8 0

3 years ago

Can someone please help me

Butoxors [25]

Answer:

1a. 58/99

1b. 53/90

1c. 29/50

Step-by-step explanation:

let's start with the easiest one

1.(c)

0.58 = 58/100 = 29/50

that is the simplest possible form, as 29 is a prime number and not a factor of 50.

1.(a)

0.585858585858... = 58×0.0101010101010101...

now, we know that 1/"double digit" (like 1/22) mostly produces a repeating pattern with a period length of 2 after the decimal point.

and we find

1/99 = 0.01010101010101...

so, our solution is

58 × 1/99 = 58/99

that is the simplest possible form, as 58 and 99 do not share any factors.

1.(b)

0.5888888888888... = 0.5 + 0.0888888888888... =

= 0.5 + 8×0.01111111111111... = 0.5 + 8×1/10 × 0.1111111111...

we know how to create 0.11111111111... :

1/9 = 0.111111111111111...

so, our solution is

0.5 + 8 × 1/10 × 1/9 = 0.5 + 8/90 = 5/10 + 8/90 =

= 45/90 + 8/90 = 53/90

this is the simplest possible form, as 53 is already a prime number and not a factor of 90.

8 0

2 years ago

Factorize the following expression ab-a-b+1

dolphi86 [110]

Group 'em together

a b − a + 1 − b

a b − a = a ( b − 1 )

Notice that there will be a 1 as without it it'll simply be ab

1 − b = 1 ( 1 − b )

Notice that it doesn't match with the upper one... so we'll change the signs

1 ( 1 − b ) = − 1 ( b− 1 )

(try to multiply them now!!

Jot them down in one expression

a ( b − 1 ) − 1 ( b − 1 )

You get!!!!!!

( a − 1 ) ( b − 1 )

5 0

3 years ago

10 points!!HELPP ME PLEASE ❗️❗️4. Figure HJKL - Figure PQRS