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dybincka [34]
2 years ago
7

10 points!!HELPP ME PLEASE ❗️❗️4. Figure HJKL - Figure PQRS

Mathematics
1 answer:
umka21 [38]2 years ago
7 0

Answer:

B I think b djdjdjdjddhjssj

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You start driving north for 16 miles, turn right, and drive east for another 30 miles. At the end of driving, what is your strai
Maru [420]

The distance between starting and ending point is 34 miles.

Step-by-step explanation:

Given,

Car moves 16 miles to north then 30 mile to east.

It forms a right angle triangle.

The straight line distance from starting to ending point represents hypotenuse.

To find the distance between starting and ending point.

Formula

By <em>Pythagoras theorem,</em>

h² = b²+l² where h is the hypotenuse, b is base and l is the another side.

Taking, b=16 and l=30 we get,

h² = 16²+30²

or, h = \sqrt{256+900}

or, h = \sqrt{1156} = 34

Hence,

The distance between starting and ending point is 34 miles.

5 0
3 years ago
Marcos charges $6 an hour to work in his neighborhoods gardens. Complete the graph to show proportional relationship of the amou
NISA [10]

Answer:

120

Step-by-step explanation:

6 0
3 years ago
The rate of change of the function f(x) = 8 sec(x) + 8 cos(x) is given by the expression 8 sec(x) tan(x) − 8 sin(x). Show that t
liq [111]

Answer:

Shown - See explanation

Step-by-step explanation:

Solution:-

- The given form for rate of change is:

                              8 sec(x) tan(x) − 8 sin(x).

- The form we need to show:

                              8 sin(x) tan2(x)

- We will first use reciprocal identities:

                              8\frac{sin(x)}{cos^2(x)} - 8sin(x)

- Now take LCM:

                            8\frac{sin(x)- sin(x)*cos^2(x)}{cos^2(x)}

- Using pythagorean identity , sin^2(x) + cos^2(x) = 1:

                            8*sin(x)*\frac{1- cos^2(x)}{cos^2(x)} = 8*sin(x)*\frac{sin^2(x)}{cos^2(x)}

- Again use pythagorean identity tan(x) = sin(x) / cos(x):

                            8*sin(x)*tan^2(x)

8 0
3 years ago
Read 2 more answers
HELP PLEASE <br><br> Answer choices <br><br> A). 12<br><br> B). 2<br><br> C). 6<br><br> D). 25/3
I am Lyosha [343]
That is 6 I believe

3 squared equals 9
9*2=18
18/3=6
4 0
3 years ago
The endpoints of `bar(EF)` are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of `bar(EF)`?
Hoochie [10]

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are (x_{1}, y_1) and (x_2, y_2) then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:

(\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})

Thus for our question the endpoints are (x_E, y_E) and (x_F, y_F) and hence the midpoint will be:

(x_M, y_M)=(\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})

Thus, Option C is the correct option.

6 0
3 years ago
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