All categories

3 years ago

This graph shows the relationship between the number of cubic yards and total cost of topsoil at a garden shop.

Mathematics

1 answer:

Vlada [557]3 years ago

8 0

Answer: y=30x

top soil is 5 more dollars than mulch

Step-by-step explanation:

to find y=30x

see what y equals when x equals 1

You might be interested in

A pair of shoes is on sale for 15% off. With this discount, customers will save

mezya [45]

$9 is the part, 15% is the percent, and $60 is the whole

$9 is %15 of the whole. This means $9 is the part, 15% is the percent, and the whole is the total cost of the shoes after the discount. The total cost of the shoes after the discount is 60.

8 0

3 years ago

Suppose a jar contains 7 red marbles and 21 blue marbles. if you reach in the jar and pull out 2 marbles at random at the same t

Anit [1.1K]

The probability is 1 out of 3 chance.

4 0

3 years ago

Read 2 more answers

At the beginning of summer, Mark has $200 in savings and Ryan has $350. The brothers have mowing jobs set up for the summer. Bec

xz_007 [3.2K]

Answer:

30 jobs

Step-by-step explanation:

Mark

Initial amount - $200
Earning - $20*j
Saving is: S = 20j + 200

Ryan

Initial amount - $350
Earning - $15*j
Saving is: S = 15j + 350

If they get same saving, then the equations will be equal:

20j + 200 = 15j + 350
20j - 15j = 350 - 200
5j = 150
j = 150/5
j = 30

The answer is 30 mowing jobs

5 0

3 years ago

Casey buys bracelet space for the bracelet and pays $0.72 sales tax the sales tax is 6% what is the original price of the bracel

nekit [7.7K]

This is my go at the problem.

Let x be the original price.

72/100=6/100 of x.
so,
x=72/100 ÷ 6/100= $12.00

The answer is $12.00

Hope this helps!

3 0

3 years ago

If a polynomial function f(x) has roots -8, 1, and 6i, what must also be a root of f(x)?

Naddik [55]

Answer:

it must also have the root : - 6i

Step-by-step explanation:

If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.

This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:

$(x-(a+bi))*(x-(a-bi))=\\(x-a-bi)*(x-a+bi)=\\([x-a]-bi)*([x-a]+bi)=\\(x-a)^2-(bi)^2=\\(x-a)^2-b^2(-1)=\\(x-a)^2+b^2$

where the imaginary unit has disappeared, making the expression real.

So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)

Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.

5 0

3 years ago