Day 3 is A because it tell how many pieces of candies eaten in a minute.
Day 4 is 10 and 15 because the ratios go in a pattern by 5
Day 5 is D but I really dont know that one
This is an equation in STANDARD form for a circle:
(x-h)^2 + (y-k)^2 = r^2
The values of (h, k) are the center point of the circle. When they are put into an equation, their symbols flip as in, if they are positive on a graph, they become negative in the equation and vice versa.
The value (r) is the radius and is squared in the equation. In this case, the square root of 1 is 1.
(x)^2 + (y-6)^2 = 1
C(-8,2) and M(0,0) , since M is at the origin. Let x₁ and y₁ be the
coordinates of S →s(x₁ , y₁)
C(-8,2) and S(x₁ , y₁)
The coordinates of M, the midpoint of CS are M(x₂ , y₂)
a) x₂ = (-8 + x₁)/2 , but x₂ = 0, then :
0 = -4+x₁/2 and x₁ = 8
b) y₂ = (2+y₁)/2 , but y₂ = o, then:
0 = 2+ y₁/2 and y₂ = -2
Then the coordinates of S are S(8 , -2)
The answer is x=6. I double checked the work and am 100% sure thats the answer
Answer:
A graph that has an axis of symmetry at x = 3 would be x^2 -6x + 12
Step-by-step explanation:
In order to find a graph that has an axis of symmetry at 3, use the equation for the axis of symmetry of a quadratic.
x = -b/2a
In this equation, a is the coefficient of x^2 and b is the coefficient of x. So, if we use 3 as x and we choose a random number to be a (1), we can solve for the b.
3 = -b/2(1)
3 = -b/2
6 = -b
b = -6
Now that we have this, we can put those two numbers as coefficients. The constant at the end can be anything.
