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Leto [7]
2 years ago
11

For which equations below is x = -3 a possible solution? Select three options.

Mathematics
2 answers:
USPshnik [31]2 years ago
7 0

Answer:

Only -lxl = -3 works

Step-by-step explanation:

The other options don't work because they all have numbers inside of the absolute value brackets.  You would always get a positive end value when the absolute value equation is applied.

The last one is the only one that works because the negative is outside of the absolute value bracket.  Therefore, if you plug in 3 for x, it will give you -3.

yaroslaw [1]2 years ago
4 0

Answer:

-|x|=-3

|x|=-3

|-x|=-3

Step-by-step explanation:

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Consider this exponential equation:
ioda

Step-by-step explanation:

F( <em>x</em><em> </em><em>)</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>(</em><em>3</em><em>)</em><em> </em><em>^</em><em> </em><em>x</em>

<em>Y</em><em> </em><em>intercept</em><em> </em>

<em>Let</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>0</em>

<em>f</em><em>(</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>5</em><em>×</em><em> </em><em>3</em><em> </em><em>^</em><em> </em><em>0</em>

<em>f</em><em>(</em><em>0</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>1</em>

<em>f</em><em>(</em><em>0</em><em>)</em><em> </em><em>=</em><em> </em><em>5</em>

<em>X</em><em> </em><em>intercept</em><em> </em>

<em>let</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>o</em>

<em>0</em><em> </em><em>=</em><em> </em><em>5</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>^</em><em>x</em>

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<em>therefore</em><em> </em>

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<em>Domain</em><em> </em><em>XER</em>

<em>▪︎</em><em>this</em><em> </em><em>refer</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>X</em>

4 0
2 years ago
How many real-number solutions does the equation have?
Nataly_w [17]

Answer:

Option b. Two solutions

Step-by-step explanation:

In order to find how many real number solutions the equation has we have to solve it

Given equation: -4x² + 10x + 6 = 0

taking 2 common from the equation

2(-2x² + 5x + 3) = 0

-2x² + 5x + 3 = 0

taking minus sign common from the above equation

2x² - 5x - 3 = 0

We will solve this equation by factorization in such a way that the sum of two factors is equal to -5x and the product is -6x²

2x² - 6x + x - 3 = 0

taking common above

2x(x-3) + 1(x-3) = 0

taking (x-3) common

(2x+1)(x-3) = 0

2x + 1 = 0

2x = -1

x = \frac{-1}{2}

x - 3 = 0; x = 3

the solutions are

x=\frac{-1}{2},3

Both values are real numbers, therefore correct option is b

7 0
3 years ago
Read 2 more answers
What is the square root of:<br><br>a) 58.82<br>b) 10
natka813 [3]
Square root of A= 7.66 ( Took the first 2 numbers after the decimal.)
Square root of B= 3.16 (Took the first 2 numbers after the decimal.)
HOPE THIS HELPS! ^_^
7 0
3 years ago
The length of a rectangle is shown below:
Wittaler [7]
It would be A because it is 5 units down from the points
7 0
2 years ago
Please help i have exam tom. ​
Xelga [282]

Answer:

Step-by-step explanation:

this is a simultaneous equation question

f(1)=8  so  a(1) + b = 8

f(4)=17 so a(4) + b = 17

can you figure this out from here ???

if you can't below is how to solve it

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|

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|

|

|

|

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a + b = 8

4a+b=17

multiply the top equation by 4 and then subtract the bottom one from the top

4a+4b = 32

-(4a +b = 17)

3b = 15

b=5

now plug 5 into the first equation

a + 5 = 8

a=3

there you go :)

3 0
3 years ago
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