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g100num [7]
2 years ago
15

C. How many tiles would be in Figure 97? If my equation is y=3x+1

Mathematics
1 answer:
Arisa [49]2 years ago
3 0
There would be
y=3x+1
y=3(97)+1
y=291+1
y=292
:D
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What are the domain and range of the inequality y < sqrt x+3+1
love history [14]

Given:

The inequality is:

y

To find:

The domain and range of the given inequality.

Solution:

We have,

y

The related equation is:

y=\sqrt{x+3}+1

This equation is defined if:

x+3\geq 0

x\geq -3

In the given inequality, the sign of inequality is <, it means the points on the boundary line are not included in the solution set. Thus, -3 is not included in the domain.

So, the domain of the given inequality is x>-3.

We know that,

\sqrt{x+3}\geq 0

\sqrt{x+3}+1\geq 0+1

y\geq 1

The points on the boundary line are not included in the solution set. Thus, 1 is not included in the range.

So, the domain of the given inequality is y>1.

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A line passes through the origin and has a slope of -3 what is the equation of the line that is perpendicular to the first line
Marianna [84]

Answer: y=\frac{1}{3}x+3

Step-by-step explanation:

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The slopes of perpendicular lines are negative reciprocal.

Then, if the slope of the first line is -3, the slope of the other line must be:

m=\frac{1}{3}

Substitute the point (3,4) into the equation and solve for b:

4=\frac{1}{3}(3)+b\\ 4-1=b\\b=3

Then the equation of this line is:

y=\frac{1}{3}x+3

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