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3 years ago

Show that the sum of two irrational numbers can be rational

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

7 0

Answer:

Hint: We will have to know about the rational numbers and irrational numbers. ... So, the sum of the given two irrational numbers is equal to 6 which is a rational number in the form of p/q where p=6 and q=1 both are integers. Therefore, it is proved that the sum of the two given irrational numbers is a rational number.

Step-by-step explanation:

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$4 - 5 / 2 * (1/10x) = 1\\$

The first step is to identify the order in which the equation must be solved, by following PEMDAS (you might know it as BEDMAS):

Parenthesis (or Brackets)

Exponents

Multiplication and Division

Addition and Subtraction

My advice would be to add parenthesis, following these rules, if you are not very good at finding them immediately by sight.

So:

$4 - 5 / 2 * (\frac{1}{10x}) = 1\\\\4 - [(5/2)*(\frac{1}{10x})]=1\\\\4-(2.5*\frac{1}{10x})=1\\\\4-\frac{2.5}{10x}-1=0\\3-\frac{x}{4}=0\\\frac{x}{4}=3\\x=3*4\\x=12$

We check our answer:

$x=12\\4 - [(5 / 2) * (1/10)*(x)] = 1\\4 - [(5 / 2) * (\frac{1}{10}) * (12))] = 1\\4 - [2.5 * (\frac{1}{10})*12] = 1\\4 - [(\frac{2.5}{10})*12] = 1\\4 - [(\frac{1}{4})*12] = 1\\4 - 3 = 1\\1=1$

We are right!

So, $x=12$ .

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3 years ago

Show that the sum of two irrational numbers can be rational ​

Show that the sum of two irrational numbers can be rational