X² - 7x + 10 = 0
Let's factor out the equation first.
x² - 7x + 10
x -2
x -5
This factoring of (x-2)(x-5) fit the equation.
(x-2)(x-5) = 0
One of the factors must equal 0 as to equal zero.
Either x - 2 = 0 or x - 5 = 0
x - 2 = 0
x = 2
x - 5 = 0
x = 5
The two answers are x = 2 or x = 5. Hope this helps!
5 the answer I took the test
Simplifying
5x(4y + 3x) = 5x(3x + 4y)
Reorder the terms:
5x(3x + 4y) = 5x(3x + 4y)
(3x * 5x + 4y * 5x) = 5x(3x + 4y)
Reorder the terms:
(20xy + 15x2) = 5x(3x + 4y)
(20xy + 15x2) = 5x(3x + 4y)
20xy + 15x2 = (3x * 5x + 4y * 5x)
Reorder the terms:
20xy + 15x2 = (20xy + 15x2)
20xy + 15x2 = (20xy + 15x2)
Add '-20xy' to each side of the equation.
20xy + -20xy + 15x2 = 20xy + -20xy + 15x2
Combine like terms: 20xy + -20xy = 0
0 + 15x2 = 20xy + -20xy + 15x2
15x2 = 20xy + -20xy + 15x2
Combine like terms: 20xy + -20xy = 0
15x2 = 0 + 15x2
15x2 = 15x2
Add '-15x2' to each side of the equation.
15x2 + -15x2 = 15x2 + -15x2
Combine like terms: 15x2 + -15x2 = 0
0 = 15x2 + -15x2
Combine like terms: 15x2 + -15x2 = 0
0 = 0
Solving
0 = 0
Couldn't find a variable to solve for.
This equation is an identity, all real numbers are solutions.
I think it’s 720 check and see if it’s rightfully
