1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
gregori [183]
3 years ago
15

Write python program to find sum(using while/loop): sum= 1+ 2+ 4+8+ 16+ 32+....1024

Computers and Technology
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer:

i = 0

total = 0

while i <= 10:

   total += pow(2, i)

   

   i += 1

print(total)

Explanation:

When you look the equation, you would realize that it is the sum of the numbers that are 2 to the power of i where 0 <= i <= 10

Set i and total as 0

Create a while loop that iterates while i is smaller than or equal to 10. Add the 2 to the power of i to the total (cumulative sum). Note that we use pow() method to calculate the power. At the end of the loop, increment the i by 1. Otherwise the loop will be an infinite loop.

When the loop is done, print the total

You might be interested in
It is a good idea to include your teacher’s name on a title page.
LenaWriter [7]

Answer: I think it all depends on the teacher because I know one of my teachers like when we put their name on our assignments. So I pick true

Explanation:

6 0
3 years ago
Read 2 more answers
John would like to move from the suburbs into the city, but the rent in the city is very high. John has found an apartment he re
maxonik [38]

A list of multiple choices is given;

<span>a)      </span>Purchase a home in the city center instead.

<span>b)      </span>Rent the apartment anyway.

<span>c)       </span>Rent the apartment with a roommate.

<span>d)      </span>Purchase a home in the suburbs instead.


The answer is (C)


John should look for an apartment and share it with a roommate. This will bring down rent expenses to 50% as both John and the roommate will be cost sharing the rent. If the rent expenses go down by 50%, he’ll be able to save an additional 10% and use it for other expenses.

4 0
3 years ago
On the Audio Tools contextual tab, which tab will control how the audio file appears, if it appears, on the slide
MrMuchimi
B is the correct answer
5 0
3 years ago
Read 2 more answers
Implement a Breadth-First Search of the people in the network who are reachable from person id 3980. You can implement BFS with
Gnoma [55]

Answer:

Check the explanation

Explanation:

import java.io.File;

import java.io.FileNotFoundException;

import java.util.LinkedList;

import java.util.Scanner;

import static org.junit.Assert.assertEquals;

/**

* CS146 Assignment 3 Node class This class is used for undirected graphs

* represented as adjacency lists The areFriends() method checks if two people

* are friends by checking if an edge exists between the two

*

*/

public class NetworkAdjList {

   // Initialize array with max number of vertices taken from SNAP

   static int max_num_vertices = 88234;

   static LinkedList<Integer>[] adjacencyList = new LinkedList[max_num_vertices];

   public static void createAdjacencyList() {

       // Initialize array elements

       for (int j = 0; j < max_num_vertices; j++) {

           adjacencyList[j] = new LinkedList<Integer>();

       }

       // Get file path of the 3980.edges file

       String filePath = "C:\\Users\\shahd\\Documents\\CS146\\Assignment 3\\Question 3\\Question3\\src\\a3\\3980.edges";

       File f = new File(filePath);

       // Use Scanner to read edges from the file and put it into adjacency list

       int a;

       int b;

       try {

           Scanner fileIn = new Scanner(f);

           while (fileIn.hasNext()) {

               a = fileIn.nextInt();

               b = fileIn.nextInt();

               adjacencyList[a].add(b);

               adjacencyList[b].add(a); // We need to add the edges both ways

           }

       } catch (FileNotFoundException e) {

           e.printStackTrace();

       }

   }

   public static boolean areFriends(int A, int B) {

       // If the adjacency list contains (A, B) edge, then return true, else false

       if (adjacencyList[A].contains(B)) {

           return true;

       } else {

           return false;

       }

   }

  private static void bfsHelper(boolean visited[], int currentNode, int dis, int sourceNode) {

       dis++;

       if(!visited[currentNode]) {

           visited[currentNode] = true;

           

           for(int neighbor: adjacencyList[currentNode]) {

               System.out.println(neighbor + " is at a distance of " + dis + " from " + sourceNode);

               bfsHelper(visited, neighbor, dis++, sourceNode);

           }

       }

   }

   public static void BFStraversal(int start) {

       boolean visited[] = new boolean[max_num_vertices];

       bfsHelper(visited, start, 0, start);

   }

   public static void main(String[] args) {

       /**

        * These test cases assume the file 3980.edges was used

        */

       createAdjacencyList();

       System.out.println("Testing...");

       assertEquals(areFriends(4038, 4014), true);

       System.out.println("1 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(3982, 4037), true);

       System.out.println("2 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(4030, 4017), true);

       System.out.println("3 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(4030, 1), false);

       System.out.println("4 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(1, 4030), false);

       System.out.println("5 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(4003, 3980), true);

       System.out.println("6 of 7");

       System.out.println("Testing...");

       assertEquals(areFriends(3985, 4038), false);

       System.out.println("7 of 7");

       System.out.println("Success!");

   }

}

**************************************************

8 0
3 years ago
Compare the current in two lightbulbs wired in a series circuit
julia-pushkina [17]
<span>The current flow in two light bulbs wired in a series circuit is identica</span>
7 0
3 years ago
Other questions:
  • HELP ASAP- YOU GET BRAINLIEST!!
    13·1 answer
  • When an IPv6 device with no pre-configured IPv6 address powers up, it can calculate a global 128-bit IPv6 address for itself usi
    12·1 answer
  • Create an application that writes a series of random numbers to a file. Each random number should be in the range of 1 through 1
    9·1 answer
  • Which commands are on the right-most side of the Title bar? (From Microsoft Word)
    9·1 answer
  • Complete the code.
    12·2 answers
  • Type of file containing instructions that tell your computer how to perform ___
    9·1 answer
  • If you wouldn't want someone to photograph you doing something, don't photograph someone else in that situation either. True Fal
    5·1 answer
  • What are the main dimensions of information system and their components
    13·1 answer
  • Difference between batabse and database management system
    5·1 answer
  • Does putting a glue stick on your touchpad make it stop working pls help
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!