<span>Any software or program that comes in many forms and is designed to disrupt the normal operation of a computer by allowing an unauthorized process to occur or by granting unauthorized access is known as: Malicious code
Malicious code is often created to steal some information from another user without they realizing it, such as address, credit card number, social security number, email password, etc.</span>
Answer:
spanning-tree portfast bpduguard
Explanation:
spanning- tree protocol (STP) is a layer 2 protocol in the OSI model. It is automatically configured in a switch to prevent continual looping of BPDUs, to avoid traffic congestion. The fastport bpduguard is only applicable in non-trunking access in a switch. It is more secure to configure the fastport mode in switch port connected directly to a node, because there are still bpdus transfer in a switch to switch connection.
BPDUs Guard ensures that inferior bpdus are blocked, allowing STP to shut an access port in this regard.
I type of shape, or a pointing index finger
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
