Question

Solve the equation.20-%20246%20%3D%200%20%5C%5C%20" id="TexFormula1" title=" {3}^{4(m + 1)} + {3}^{4m} - 246 = 0 \\ " alt=" {3}^{4(m + 1)} + {3}^{4m} - 246 = 0 \\ " align="absmiddle" class="latex-formula">
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Answer 1

$3^{4m+4}+3^{4m}=246\\ (3^{4}+1)*3^{4m}=246\\82*3^{4m}=246\\3^{4m}=3\\m=\frac{1}{4}$

Answer 2

You group them since they have the same base (3). (3^4+1)*3^4m since they have almost the similar characters (ex. 3^4(m+1) is 3^4m+4). In the brackets we get (81+1) since 3^4 is 81, then we do the sum in the brackets (81+1) is 82 multiplied by 3^4m. Then we divide both sides with /82. 82/82 is one, 256/82 is 3. Since 3^4m and 3^1 have the same bases we just use 4m=1 where we get that m is 1/4.