Question

If the measurment of the angles of a triangle are 3b,2b,and 4b then what is the smallest angle

Answer 1

Given:

The measurement of the angles of a triangle are 3b,2b,and 4b.

To find:

The smallest angle.

Solution:

According to the angle sum property, the sum of all angles of a triangle is 180 degrees.

$3b+2b+4b=180^{\circ}$           [Angle sum property]

$9b=180^{\circ}$

Divide both sides by 9.

$b=20^{\circ}$

Now,

$3b=3(20^{\circ})=60^{\circ}$

$2b=2(20^{\circ})=40^{\circ}$

$3b=4(20^{\circ})=80^{\circ}$

Therefore, the smallest angle is 40 degrees.