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jeka94
3 years ago
8

If the measurment of the angles of a triangle are 3b,2b,and 4b then what is the smallest angle

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0

Given:

The measurement of the angles of a triangle are 3b,2b,and 4b.

To find:

The smallest angle.

Solution:

According to the angle sum property, the sum of all angles of a triangle is 180 degrees.

3b+2b+4b=180^{\circ}           [Angle sum property]

9b=180^{\circ}

Divide both sides by 9.

b=20^{\circ}

Now,

3b=3(20^{\circ})=60^{\circ}

2b=2(20^{\circ})=40^{\circ}

3b=4(20^{\circ})=80^{\circ}

Therefore, the smallest angle is 40 degrees.

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