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lina2011 [118]
3 years ago
9

Find the area of this parallelogram​

Mathematics
1 answer:
mixer [17]3 years ago
5 0

Answer:

Area of this parallelogram​ A = base x height = 11 x 6 = 66 (cm2)

Hope this helps!

:)

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just olya [345]

??? what do u mean

like numbers in the thousands place is 3


8 0
3 years ago
Read 2 more answers
−7(7+5x)+x=−3x−18 what does x =
Eduardwww [97]

Answer:

-1

Step-by-step explanation:

-49-35x+x=-3x-18

-49-34x=-3x-18

-34x+3x=-18+49

-31x=31

-31x/-31=31/-31

ansx=-1

pliz mark my answer brainliest

4 0
3 years ago
1. Solve: -3x + 1 = 7
aksik [14]

Answer:

1. -2 = x

2. 19 = x

3. -22 = b

4. 30 = y

5. -5 = t

Step-by-step explanation:

1. -3x = 6 [-1 to the right side of the equivalence symbol]

2. 5x = 95 [23 to the right side of the equivalence symbol]

3. ᵇ/₂ = -11 [23 to the left side of the equivalence symbol]

4. ⅓y = 10 [7 to the right side of the equivalence symbol]

5. -2t = 10 [13 to the right side of the equivalence symbol]

I am joyous to assist you anytime.

7 0
3 years ago
Question 2 says: With out multiplying, determine the sign of the product
DiKsa [7]
Count the negative signs, if you get an odd number of negative signs, the product is a negative. If you get an even number of negative signs, the product is a positive. 
in this case, there are two negatives, the the product is a positive number
3 0
3 years ago
Consider the line y = 7x-9.
KatRina [158]

y = \frac{-1}{7}x -\frac{8}{7} is the equation of the line that is perpendicular to this line and passes through the point (6, -2)

y = 7x - 44 equation of the line that is parallel to this line and passes through the point (6, -2)

<em><u>Solution:</u></em>

<em><u>Given that line is:</u></em>

y = 7x - 9

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + b ------ eqn 1

Where, "m" is the slope of line and "b" is the y intercept

On comparing eqn 1 with y = 7x - 9 we get,

m = 7

<h3><u>Find the equation of the line that is perpendicular to this line and passes through the point (6, -2)</u></h3>

We know that,

Product of slope of a line and slope of line perpendicular to given is always -1

Therefore,

7 \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{-1}{7}

Now find the equation of line:

\text{ Substitute } m = \frac{-1}{7} \text{ and } (x, y) = (6, -2) \text{ in eqn 1}

-2 = \frac{-1}{7} \times 6 + b\\\\-2 = \frac{-6}{7} + b\\\\b = -2+\frac{6}{7}\\\\b = \frac{-14+6}{7}\\\\b = \frac{-8}{7}

\text{Substitute } m = \frac{-1}{7} \text{ and } b = \frac{-8}{7} \text{ in eqn 1}\\\\y = \frac{-1}{7}x -\frac{8}{7}

Thus the equation of line perpendicular to given line is found

<h3><u>Find the equation of the line that is parallel to this line and passes through the point (6, -2)</u></h3>

Slopes of parallel lines are equal

Therefore,  m = 7

<em><u>Substitute m = 7 and (x, y) = (6, -2) in eqn 1</u></em>

-2 = 7(6) + b

-2 = 42 + b

b = -44

<em><u>Substitute m = 7 and b = -44 in eqn 1</u></em>

y = 7x - 44

Thus equation of line parallel to given line is found

8 0
3 years ago
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