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den301095 [7]
3 years ago
13

0= - z/3 + 4 Can you help me?

Mathematics
2 answers:
kkurt [141]3 years ago
8 0

Answer:

Step-by-step explanation:

Jd

scoundrel [369]3 years ago
6 0

Answer:

z=12

Step-by-step explanation:

subtract both sides by 4:

-z/3=-4

then multiply both sides by -3:

z=12

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If the frequency of two alleles in a gene pool is 90%A and 10% a, what is the frequency of individuals in the population with th
Sladkaya [172]

Answer: 0.18

Step-by-step explanation:

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7 0
3 years ago
the baker's at healthy bakery can make 190 bagels in 2 hours how many bagels can they bake in 20 hours what was the rate per hou
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Answer:

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5 0
3 years ago
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Find the probability of getting four consecutive aces when four cards are drawn without replacement from a standard deck of 52 p
posledela

Answer:

<em>P=0.0000037</em>

<em>P=0.00037%</em>

Step-by-step explanation:

<u>Probability</u>

A standard deck of 52 playing cards has 4 aces.

The probability of getting one of those aces is

\displaystyle \frac{4}{52}=\frac{1}{13}

Now we got an ace, there are 3 more aces out of 51 cards.

The probability of getting one of those aces is

\displaystyle \frac{3}{51}=\frac{1}{17}

Now we have 2 aces out of 50 cards.

The probability of getting one of those aces is

\displaystyle \frac{2}{50}=\frac{1}{25}

Finally, the probability of getting the remaining ace out of the 49 cards is:

\displaystyle \frac{1}{49}

The probability of getting the four consecutive aces is the product of the above-calculated probabilities:

\displaystyle P= \frac{1}{13}\cdot\frac{1}{17}\cdot\frac{1}{27}\cdot\frac{1}{49}

\displaystyle P= \frac{1}{270,725}

P=0.0000037

P=0.00037%

3 0
3 years ago
Round 75.64 to the nearest ten.
Dennis_Churaev [7]

Answer:75.6

Step-by-step explanation:

4 goes down

7 0
3 years ago
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A number between
butalik [34]
60

3 x 20 = 60
10 x 6 = 60
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3 years ago
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