Answer:
about 78 years
Step-by-step explanation:
Population
y =ab^t where a is the initial population and b is 1+the percent of increase
t is in years
y = 2000000(1+.04)^t
y = 2000000(1.04)^t
Food
y = a+bt where a is the initial population and b is constant increase
t is in years
b = .5 million = 500000
y = 4000000 +500000t
We need to set these equal and solve for t to determine when food shortage will occur
2000000(1.04)^t= 4000000 +500000t
Using graphing technology, (see attached graph The y axis is in millions of years), where these two lines intersect is the year where food shortages start.
t≈78 years
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Answer:
20, 30
Step-by-step explanation:
let the intergers be x and y
x = 2/3y
from this eqn, we know that y is larger.
hence, y-x=10
y-2/3y=10
1/3y=10
y=30
x=2/3y =2/3(30) = 20
Answer:
x=6
Step-by-step explanation:
Y = 1/3 x - 10 . . . (1)
2x + y = 4 . . . . . (2)
Putting (1) into (2) gives
2x + 1/3 x - 10 = 4
7/3 x = 4 + 10 = 14
x = (3 x 14)/7 = 3 x 2 = 6
x = 6
From (1), y = 1/3 (6) - 10 = 2 - 10 = -8
y = -8