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7nadin3 [17]
3 years ago
7

Long division, x^3-2x^2+1 divided x^2-x+1

Mathematics
1 answer:
Bad White [126]3 years ago
7 0

Step-by-step explanation:

i think this the answer. if it's wrong sorry

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gizmo_the_mogwai [7]

Answer:

α = π/3

γ = 2

x = -3π/4, -5π/12, π/4, 7π/12

Step-by-step explanation:

Easiest way to do this is in reverse.

γ sin(2x − α)

Angle sum/difference formula:

γ (cos α sin(2x) − sin α cos(2x))

Distribute:

γ cos α sin(2x) − γ sin α cos(2x)

Matching the coefficients:

γ cos α = 1

γ sin α = √3

Solve the system of equations.  Divide to eliminate γ:

tan α = √3

α is between 0 and π/2, so:

α = π/3

γ = 2

sin(2x) − √3 cos(2x) = 1

Using the identity from before:

2 sin(2x − π/3) = 1

Solving:

sin(2x − π/3) = 1/2

2x − π/3 = π/6 + 2kπ or 5π/6 + 2kπ

2x = π/2 + 2kπ or 7π/6 + 2kπ

x = π/4 + kπ or 7π/12 + kπ

x is between -π and π, so:

x = -3π/4, -5π/12, π/4, 7π/12

7 0
3 years ago
What is the lateral surface area on a square pyramid with base edges of 10 and the height of 12
8_murik_8 [283]

Answer:

joe mama

Step-by-step explanation:

7 0
2 years ago
Ok, I would really like some help ^.^ If you could and have the time...would you mind breaking down the answer for me please, he
uysha [10]

Answer:

C

Step-by-step explanation:

4 x 4=16 and half of 4 is 2 so the answer is C)4

5 0
3 years ago
Read 2 more answers
Write an expression for the apparent nth term of the sequence 0, 3, 8, 15, 24
Finger [1]
S=i(n-1)+2*(n-1)+1 perhaps
6 0
3 years ago
a 136 foot tall cell phone tower casts a 79.9 foot shadow. find the shadow length for a nearby 40 foot telephone pole
AleksAgata [21]

Given :

A 136 foot tall cell phone tower casts a 79.9 foot shadow.

To Find :

The shadow length for a nearby 40 foot telephone pole .

Solution :

We know , the ratio of height and shadow , will be same for every object .

Let , length of shadow of pole is x .

So ,

\dfrac{79.9}{136}=\dfrac{x}{40}\\\\x=\dfrac{79.9\times 40}{136}\ foot\\\\x=23.5\ foot

Therefore , the length of shadow of tower is 23.5 foot .

Hence , this is the required solution .

3 0
3 years ago
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