Answer:
0.278 mol
Explanation:
Step 1: Given and required data
Mass of acetic acid (m): 16.7 g
Chemical formula of acetic acid: CH₃COOH (C₂H₄O₂)
Step 2: Calculate the molar mass (M) of acetic acid
We will use the following expression.
M(C₂H₄O₂) = 2 × M(C) + 4 × M(H) + 2 × M(O)
M(C₂H₄O₂) = 2 × 12.01 g/mol + 4 × 1.01 g/mol + 2 × 16.00 g/mol = 60.06 g/mol
Step 3: Calculate the number of moles (n) of acetic acid
We will use the following expression.
n = m/M
n = 16.7 g/(60.06 g/mol) = 0.278 mol
Answer:
450g of coke (C)
Explanation:
Step 1:
The balanced equation for the reaction is given below:
3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)
Step 2:
Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.
This is illustrated below:
Molar Mass of C = 12g/mol
Mass of C from the balanced equation = 3 x 12 = 36g
Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Step 3:
Determination of the mass of C required to produce 950g of CS2. This is illustrated below:
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Therefore, Xg of C will react to produce 950g of CS2 i.e
Xg of C = (36 x 950)/76
Xg of C = 450g
From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.
Answer:
2 KNO₃ + 10 K → 5 K₂O + N₂ (option 1)
Explanation:
1. 2 KNO₃ + 10 K → 5 K₂O + N₂
We have in reactant side:
2 K, 2N, 6O and 10 K. In conclussion, 12 K, 2N and 6 O
We have in product side.
10 K, 5O and 2 N
This equation is unbalanced
2. 2 SO₂ + O₂ → 2 SO₃
In reactant side we have 2 S and 6 O
In product side we have 2 S and 6 O
3. SF₄ + 3 H₂O → H₂SO₃ + 4 HF
In reactant side we have 1 S, 4F, 6 H and 3 O
In product side we have 1 S, 4F, 6 H and 3 O
Sodium loses an electron and chlorine gains an electron.
Hope this helps!
Answer:
51 J
Explanation:
The air inside a bicycle tire pump has 27 joules of heat conducted away. By convention, when heat is released, it takes the negative sign, so Q = -27 J.
77.9 joules of work done are being done on the air inside a bicycle tire pump. By convention, when work is being done on the system, it takes the positive sign, so W = 77.9 J
We can calculate the change in the internal energy (ΔU) using the following expression.
ΔU = Q + W
ΔU = (-27 J) + 77.9 J
ΔU = 51 J
