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Diano4ka-milaya [45]
3 years ago
5

Consider the following sets of sample data: A: $36,700, $30,300, $22,800, $27,700, $37,700, $39,800, $27,000, $30,100, $33,900,

$24,900, $27,500, $37,600, $32,700, $34,200 B: 21,253, 21,065, 20,747, 21,905, 20,546, 21,580, 22,292, 20,072, 20,518, 20,426, 20,839 Step 1 of 2 : For each of the above sets of sample data, calculate the coefficient of variation, CV. Round to one decimal place.
Mathematics
1 answer:
maksim [4K]3 years ago
5 0

Answer:

16.6% ; 3.2%

Step-by-step explanation:

Given the data :

Data A:

$36,700, $30,300, $22,800, $27,700, $37,700, $39,800, $27,000, $30,100, $33,900, $24,900, $27,500, $37,600, $32,700, $34,200

Data B: 21,253, 21,065, 20,747, 21,905, 20,546, 21,580, 22,292, 20,072, 20,518, 20,426, 20,839

The Coefficient of variation (CV) = (Sample standard deviation / Sample mean)

Sample mean (m) ;

Σx / n

n = sample size

Sample standard deviation (S) :

√[(x - m)² / (n-1)]

To save computation time ;

The sample mean and sample standard deviation can be obtained using a calculator :

For Data A:

Sample mean (m) = 31635.7143

Sample Standard deviation (s) = 5256.14763

Hence, Coefficient of variation :

5256.14763 / 31635.7143

= 0.166

= 0.166 * 100% = 16.6%

For Data B:

Sample mean (m) = 21022.0909

Sample Standard deviation (s) = 678.718271

678.718271 / 21022.0909

= 0.032

= 0.032 * 100% = 3.2%

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Each bowling ball weighs 7.3*10^3 grams. The bowling alley has 2.0*10^2 bowling balls. How much do they all weigh, combined? Exp
Alexandra [31]

Answer:

1.46 x 10⁶g

Step-by-step explanation:

Given parameters:

Weight of each bowling ball  = 7.3 x 10³g

Number of balls in the bowling alley = 2.0 x 10²bowling balls

Unknown

The weight of the balls in the alley  = ?

Solution:

To find the weight of the balls in the alley, multiply the mass of each balls with the total number of balls;

 Weight of the balls = 7.3 x 10³ x 2.0 x 10²

 Weight of the balls  = (7.3 x 2.0) x 10³⁺²

 Weight of the balls  = 14.6 x 10⁵g

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3 0
3 years ago
Help me please !! i need the answer
madam [21]

Answer:

PQ=22\\\\QR=7\\\\PR=29

Step-by-step explanation:

To find the value of y, you can create an equation where two parts of the line are equal to the whole line:

PQ+QR=PR

Substitute given values:

(8y+6)+(y+5)=(19y-9)

Solve for y. Simplify parentheses:

8y+6+y+5=19y-9

Combine like terms to simplify the equation:

8y+y+6+5=19y-9\\\\9y+11=19y-9

Get the variable on one side of the equation and the constants on the other. Add 9 to both sides:

9y+11+9=19y-9+9\\\\9y+20=19y

Subtract 9y from both sides:

9y-9y+20=19y-9y\\\\20=10y

Isolate the variable. Divide both sides by 10:

\frac{20}{10} =\frac{10y}{10} \\\\y=2

The value of y is 2. Insert this value into each line segment value and solve:

PQ=8(2)+6\\\\PQ=16+6\\\\PQ=22

QR=(2)+5\\\\QR=7

PR=19(2)-9\\\\PR=38-9\\\\PR=29

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You can check by using:

PQ+QR=PR\\\\22+7=29

This statement is true, so the values are correct.

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Step-by-step explanation:

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8_murik_8 [283]

Answer:Set A: the range is 9. The mean absolute deviation is 2.88. Set B: the range is 18. The mean absolute deviation is 4.5.

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