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Serggg [28]
3 years ago
11

Solve for x.. 3(x-8) = 29.7

Mathematics
2 answers:
k0ka [10]3 years ago
8 0

\text {Hello! Let's Solve this Equation!}

\text {The First Step is to Multiply 3 in the Parentheses:}

\text {3*x=3x}\\\text {3*8=24}

\text {Your new Problem is: 3x-24=29.7}

\text {The Next Step is to Add 24:}

\text {3x-24+24=29.7+24}\\\text {=53.7}

\text {Your new Problem is: 3x=53.7}

\text {The Final Step is to Divide 3:}

\text {3x/3=53.7/3}

\text {Your Answer would be:}

\fbox {x=17.9}

\text {Best of Luck!}

mr Goodwill [35]3 years ago
6 0

Answer:

x = 17.9

Step-by-step explanation:

3x-24=29.7\\    Distribution Property\\\\3x=53.7\\\\Adding 24 to both sides\\\\x=17.9\\Divide by 3 to both sides\\\\Hope this helps:)\\

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Based on Pythagorean identities, which equation is true? A. Sin^2 theta -1= cos^2 theta B. Sec^2 theta-tan^2 theta= -1 C. -cos^2
Arturiano [62]

Answer:

D

Step-by-step explanation:

our basic Pythagorean identity is cos²(x) + sin²(x) = 1

we can derive the 2 other using the listed above.

1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)

1 + tan²(x) = sec²(x)

2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)

cot²(x) + 1 = csc²(x)

A. sin^2 theta -1= cos^2 theta

this is false

cos²(x) + sin²(x) = 1

isolating cos²(x)

cos²(x) = 1-sin²(x), not equal to sin²(x)-1

B. Sec^2 theta-tan^2 theta= -1

1 + tan²(x) = sec²(x)

sec²(x)-tan(x) = 1, not -1

false

C. -cos^2 theta-1= sin^2

cos²(x) + sin²(x) = 1

sin²(x) = 1-cos²(x), our 1 is positive not negative, so false

D. Cot^2 theta - csc^2 theta=-1

cot²(x) + 1 = csc²(x)

isolating 1

1 = csc²(x) - cot²(x)

multiplying both sides by -1

-1 = cot²(x) - csc²(x)

TRUE

3 0
3 years ago
The radius of a circle is 2 m. Find the circumference to the nearest tenth.
Y_Kistochka [10]

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Step-by-step explanation:

2 x pi/3.14x4

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3 years ago
Can someone help me plead
andrew-mc [135]

Answer:

a. 2^3

b. 3^4

c. 4^3 × 5^2

d. 9^4 × 7^2

Step-by-step explanation:

The following equations are given

a. 2 × 2× 2

b. 3 × 3 × 3 × 3

c. 4 × 4 × 4 × 5 × 5

d. 9 × 7 × 9 × 9 × 7 × 9

We need to find the index notation for the above equations

a. 2^3

b. 3^4

c. 4^3 × 5^2

d. 9^4 × 7^2

In this way it should be done

The same would be relevant

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