Question

A=1/4 and b=6 16a-4b a=1/4 and b=6 5b/32a= a=1/4 and b=6 12a+(b−a−4)=

Answer 1

Answers & Step-by-step explanation:

#1. Insert given values:

$16*\frac{1}{4} -4*6$

Simplify multiplication from left to right. Use the rule $\frac{a}{b}*c =\frac{ac}{b}$:

$\frac{16}{4}-4*6\\\\ 4-4*6$

Simplify multiplication:

$4-24$

Simplify subtraction:

$-20\\\\16a-4b=-20$

#2. Insert given values:

$\frac{5*6}{32*\frac{1}{4} }$

Simplify multiplication:

$\frac{30}{32*\frac{1}{4} }$

Simplify multiplication. Use the rule $\frac{a}{b} *c=\frac{ac}{b}$:

$\frac{30}{\frac{32}{4} }$

Simplify division:

$\frac{30}{8}$

Simplify fraction:

$\frac{15}{4} \\\\\frac{5b}{32a}=\frac{15}{4}$

#3. Insert given values:

$12*\frac{1}{4} +(6-\frac{1}{4} -4)$  

Simplify subtraction within parentheses. Convert to fractions. Use the rule $a=\frac{a}{1}$:

$\frac{6}{1} -\frac{1}{4} -\frac{4}{1}$

Make all denominators the same. Multiply top and bottom by 4 (only do this to the fractions with 1 as the denominator):

$\frac{24}{4}-\frac{1}{4}-\frac{16}{4}$

Simplify subtraction. Subtract the numerators. The denominator will stay the same:

$\frac{24}{4}-\frac{1}{4}-\frac{16}{4}=\frac{7}{4}$

Insert:

$12*\frac{1}{4} +\frac{7}{4}$

Simplify multiplication. Use the rule $\frac{a}{b} *c=\frac{ac}{b}$:

$\frac{12}{4} =3$

Insert:

$3+\frac{7}{4}$

Simplify addition. Convert the whole number to a fraction. Use the rule $a=\frac{a}{1}$:

$\frac{3}{1} +\frac{7}{4}$

Multiply top and bottom of the first term by 4:

$\frac{12}{4}+\frac{7}{4}=\frac{19}{4} \\\\12a+(b-a-4)=\frac{19}{4}$

:Done

Answer 2

4a + 6b = 10
2a - 4b = 12
4a + 6b = 10
4a - 8b = 24
4a + 6b = 10
-14b = 14
4a + 6b = 10
b = -1
4a - 6 = 10
a = 4
b = -1